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Papessa [141]
3 years ago
14

PLS HELP ASAP

Mathematics
2 answers:
madreJ [45]3 years ago
8 0

Answer:

possible

If one person got 10, ANOTHER got 50 and the others got 30, thet mean would be 30

Step-by-step explanation:

Nitella [24]3 years ago
4 0
Yes this is possible
If one person got 10, one got 50 and the rest got 30, the mean would be 30
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Find the perimeter of a square whose sides are 7.
allochka39001 [22]
Hey there,

Your question states: <span>Find the perimeter of a square whose sides are 7.

When finding the perimeter, we need to multiply each side because it is a square. So 7 times 4 would be 28

~Jurgen</span>
5 0
3 years ago
Can someone please help me . I’ll mark brainless
Amiraneli [1.4K]

Answer:

answer for a,b and c are all zero (0).

reasons for all:

zero(0) divided by any number is zero(0).

5 0
3 years ago
Which expression is equivalent to(2^3)^-5
Nady [450]

Answer:

hope this helps if not im sorry

Step-by-step explanation:

(2^3)^5

=2^(3*5)

= 2^15

3 0
3 years ago
Which expression has the same value as the one below?
anzhelika [568]
The first one is correct
3 0
3 years ago
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
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