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2 years ago

9

I don't get this one

2 answers:

olasank [31]2 years ago

5 0

It’s rhombuses and kites!

A kite is a quadrilateral with exactly two pairs of adjacent congruent sides. (This definition excludes rhombi. Some textbooks say a kite has at least two pairs of adjacent congruent sides, so a rhombus is a special case of a kite.)

ikadub [295]2 years ago

5 0

Answer:

rectangles, square, and isosceles trapezoids

Step-by-step explanation:

It's asking which shapes always have the property that two pairs of two angles next to each other are congruent.

This would be true for rectangles, square, and isosceles trapezoids.

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A trapezoid has an area of 18 square miles. The bases are 5 miles and 7 miles. Using these measurements, the height of this trap

Rudik [331]

Answer:

3 miles

Step-by-step explanation:

A trapezoid has an area of 18 square miles. The bases are 5 miles and 7 miles. Using these measurements, the height of this trapezoid is how many miles

Area of a trapezoid = 1/2 (a + b)h

The formula for the height of a trapezoid =

h = 2(A/a + b)

A = 18 square miles

a = 5 miles

b = 7 miles

h = 2(18/5 + 7)

h = 2( 18/12)

h = 2 ( 9/6)

h = 3 miles

4 0

2 years ago

Solve the problem.

Aleonysh [2.5K]

Perimiter=2(L+W)
P=2(100+120)
P=2(220)
P=440

0.1 per foot
440*0.10=44

$44

4 0

2 years ago

Read 2 more answers

Yolonda ran 4 times last week here are the distances she ran in km

Sladkaya [172]

Answer:

42.59 km

Step-by-step explanation:

Total distance = 17.9 + 6.03 + 15.66 + 3 = 42.59

8 0

1 year ago

Read 2 more answers

What is the value of c in the interval (5,8) guaranteed by Rolle's Theorem for the function g(x)=−7x3+91x2−280x−9? Note that g(5

jeyben [28]

Answer:

$\displaystyle c = \frac{20}{3}$

Step-by-step explanation:

According to Rolle's Theorem, if f(a) = f(b) in an interval [a, b], then there must exist at least one <em>c</em> within (a, b) such that f'(c) = 0.

We are given that g(5) = g(8) = -9. Then according to Rolle's Theorem, there must be a <em>c</em> in (5, 8) such that g'(c) = 0.

So, differentiate the function. We can take the derivative of both sides with respect to <em>x: </em>

<em /> $\displaystyle g'(x) = \frac{d}{dx}\left[ -7x^3 +91x^2 -280x - 9\right]$ <em />

Differentiate:

$g'(x) = -21x^2+182x-280$

Let g'(x) = 0:

$0 = -21x^2+182x-280$

Solve for <em>x</em>. First, divide everything by negative seven:

$0=3x^2-26x+40$

Factor:

<h3> $0=(x-2)(3x-20)$ </h3>

Zero Product Property:

$x-2=0 \text{ or } 3x-20=0$

Solve for each case. Hence:

$\displaystyle x=2 \text{ or } x = \frac{20}{3}$

Since the first solution is not within our interval, we can ignore it.

Therefore:

$\displaystyle c = \frac{20}{3}$

3 0

2 years ago

. Dinah bought 3 packages of ground beef. The packages weigh 3 3/4 pounds, 1 1/8 pounds, and 2 1/2 pounds. How many pounds of gr

IgorC [24]

Answer:

6 3/8

Step-by-step explanation:

Convert the fractions so that the denominators match.

$3\frac{3}{4} =3\frac{6}{8}$ , then $3\frac{6}{8}=\frac{30}{8}$

$1\frac{1}{8}=\frac{9}{8}$

$2\frac{1}{2}=\frac{3}{2}$ , then $\frac{3}{2}=\frac{12}{8}$

Add up the fractions.

$\frac{30}{8}+\frac{9}{8}+\frac{12}{8} =\frac{51}{8} =6\frac{3}{8}$

8 0

2 years ago

Read 2 more answers