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3 years ago

Choose the correct simplification of (8x4y3)2. (5 points)

Mathematics

2 answers:

adoni [48]3 years ago

7 0

Not sure what your options are but if it is
(8x^4y^3)^2 the answer should be
64x^8y^6

DanielleElmas [232]3 years ago

3 0

Answer:

the person below is correct 64x8y6 is the right answer

Step-by-step explanation:

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10x-9 y = 24 y=x-2 x= Y=

Stels [109]

Answer: x=6 y=4
_____________

5 0

3 years ago

A. If she buys a pair of jeans for $102.25 and two shirts that each cost $44.27

slava [35]

Answer:

$481.54

Step-by-step explanation:

672.33-(102.25+(2)44.27)

672.33-(102.25+88.54)

672.33-190.79

481.54

6 0

3 years ago

Wich one is bigger 3/3 or 7/8

MrRissso [65]

3/3=1 and 7/8 is < 1 so 3/3 is bigger

4 0

3 years ago

A computer tablet is 0.24 meter long. How long is the computer tablet in centimeters? Please show work

AysviL [449]

Answer:

1 meter equals 100 centimeters, to find out how many centimeters you want to take 0.24*100= 2.4,

Therefore; the computer tablet is 24 centimeters long.

8 0

3 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0

3 years ago