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leonid [27]
3 years ago
9

Is this geometry proof correct?? Photo attached

Mathematics
1 answer:
andreev551 [17]3 years ago
5 0

Answer:

yes I think so

Step-by-step explanation:

hope this helps sorry if i messed up

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Divide. Will mark brainliest.
horrorfan [7]

Answer:

7t^5 - t^3

6x -3 +2x/y

Step-by-step explanation:

A.  (7t^8 - t^6)/t^3

Separate into 2 fractions

(7t^8/t^3) - (t^6)/t^3

Remember a^b / a^c = a^ (b-c)

7 t^(8-3) - t^(6-3)

7t^5 - t^3

B (12x^2y - 6xy +4x^2)/2xy

Separate into 3 fractions

12x^2y/2xy - 6xy/2xy +4x^2/2xy

Remember a^b / a^c = a^ (b-c)

12/2 x^(2-1) y^(1-1) - 6/2 x/x * y/y +4/2 x^(2-1) /y

6 x y^0 -3*1*1 +2 x/y

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6x -3 +2x/y

5 0
3 years ago
Write 1,360/200 as a reapeating decimal
julia-pushkina [17]

Answer:

6.8

Step-by-step explanation:

did it

3 0
3 years ago
-7x+2y=18;6x+6y=0 in elimination form
AlexFokin [52]

Step-by-step explanation:

-7x + 2y = 18

6x + 6y = 0

21x - 6y = - 54

6x + 6y = 0

27x = -54

x = -2

6(-2) + 6y = 0

-12 + 6y = 0

6y = 12

y = 2

(-2,2)

4 0
3 years ago
The Angle of depression from the top of the flagpole to an object on the ground it's 33° if the object is 60 feet from the base
N76 [4]

Answer:

The flag pole is 38.96 feet tall.

Step-by-step explanation:

The angle of depression from the top of the flagpole to an object on the ground is 33°.

The object is 60 feet from the base of the cliff.

We need to find the height of the flag pole.

Here, base, B = 60 feet

We know that,

\tan\theta=\dfrac{P}{B}

Put all the values to find P.

P=B\times \tan\theta\\\\P=60\times \tan(33)\\\\P=38.96\ ft

So, the flag pole is 38.96 feet tall.

6 0
3 years ago
Please help this is due in 12 mins !!!?!?
MakcuM [25]
Answer: 3p = 1/2
( p + p + p ) = 1/2
8 0
3 years ago
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