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mihalych1998 [28]
3 years ago
13

Use the quadratic formula to solve for x.

Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0

Answer:

x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3

Step-by-step explanation:

Solve for x:

6 x^2 - 4 x = 1

Divide both sides by 6:

x^2 - (2 x)/3 = 1/6

Add 1/9 to both sides:

x^2 - (2 x)/3 + 1/9 = 5/18

Write the left hand side as a square:

(x - 1/3)^2 = 5/18

Take the square root of both sides:

x - 1/3 = sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3

Add 1/3 to both sides:

x = 1/3 + sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3

Add 1/3 to both sides:

Answer: x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3

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Choose the statement below that correctly compares the numbers 2.34 and 2.43.
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Answer:

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Step-by-step explanation:

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< means less than

> means greater than

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3 years ago
Which of the following is a polynomial A.x^2+2 B.(x^8-2)/(x^-2+3) C. 7x^7-2x^-4+3 D.x^x-1
EastWind [94]
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B.(x⁸-2)/(x⁻²+3)  rational function
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3 years ago
A rectangle has vertices E(-4, 8), F(2, 8), G(2, -2) and H(-4, -2). The rectangle is dilated with the origin as the center of di
Marizza181 [45]

Answer:

The dilation on any point of the rectangle is P'(x,y) = \frac{5}{2}\cdot P(x,y).

Step-by-step explanation:

From Linear Algebra, we define the dilation of a point by means of the following definition:

G'(x,y) = O(x,y) +k\cdot [G(x,y)-O(x,y)] (1)

Where:

G(x,y) - Coordinates of the point G, dimensionless.

O(x,y) - Center of dilation, dimensionless.

k - Scale factor, dimensionless.

G'(x,y) - Coordinates of the point G', dimensionless.

If we know that O(x,y) = (0,0), G(x,y) =(2,-2) and G'(x,y) =(5,-5), then scale factor is:

(5,-5) = (0,0) +k\cdot [(2,-2)-(0,0)]

(5,-5) = (2\cdot k, -2\cdot k)

k = \frac{5}{2}

The dilation on any point of the rectangle is:

P'(x,y) = (0,0) + \frac{5}{2}\cdot [P(x,y)-(0,0)]

P'(x,y) = \frac{5}{2}\cdot P(x,y) (2)

The dilation on any point of the rectangle is P'(x,y) = \frac{5}{2}\cdot P(x,y).

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3 years ago
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3 years ago
Need immediate help!!
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