Answer:
The numbers are 9, 19 and 76.
Step-by-step explanation:
Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.
The first number in terms of x:

The second number in terms of x:

If we add them all up, these 3 numbers in terms of x must be equal to 104, so:

Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:


The first number is 9, second number 19 and the third number 76.
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
It is 80,000 im not sure what you meant by "800,00"
Answer:
1302
Step-by-step explanation:
10C5 + (5C1×10C4) = 1302