PrOblem 1: Find the slope of the line containing the points: (3,-5) and (-1, -2)
1 answer:
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<h3>Refer to the diagram below</h3>
- Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
- Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
- Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
- Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
- Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.
Refer to the diagram below for examples of what I mean.
Answer:
152
Step-by-step explanation:
Hello there!
The prism shown is a triangular prism
There are many different formulas for solving for the surface area of a triangular prism but I am going to use the most simple one
Formula: SA = bh + L(s1 + s2 + s3) (found in the image)
b = base length
h = height
L = length
s1 = (same thing as the base length)
s2 and s2 = other triangle side lengths ( the base is an isosceles triangle so they are equal to each other.)
The triangular prism has the following dimensions
b = 6
h = 4
L = 8
s2 and s3 = 5
Now that we have identified each dimension we plug in the values into the formula
SA = 6*4 + 8(6+5+5)
6*4=24
8*6=48
8*5=40
40*2=80
80+48=128
128 + 24 = 152 so the surface area of the triangular prism is 152 cm²
