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otez555 [7]
3 years ago
7

<1 is supplementary to <2 and <2 is supplementary to angle <3.

Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

the answer is propfjcnrbchchdb

Step-by-step explanation:

letters were never supposed to be used in maths

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Can someone help me out? I'm stuck. i think I've got the layout but I'm not sure??<br>​
crimeas [40]

Answer:

5.83 ft

Step-by-step explanation:

Pythagorean Theorem:

a² + b² = c²

3² + 5² = c²

9 + 25 = c²

34 = c²

c ≈ 5.8309 ≈ 5.83

If my answer is incorrect, pls correct me!

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-Chetan K

4 0
3 years ago
.Given the functions f(n) = 500 and g(n) = (nine tenths)n _ 1, combine them to create a geometric sequence, an, and solve for th
weeeeeb [17]
The original functions are: f(n) = 500 and g(n) = [9/10]^(n-1)

A geometric sequence combining them is: An = f(n)*g(n) = 500*[9/10]^(n-1):

Some terms are:
A1= 500
A2 = 500*[9/10]
A3 = 500*[9/10]^2
A4 = 500*[9/10]^3
....
A11 = 500*[9/10]^10 ≈ 174.339

Answer: the third option, An = 500[9/10]^(n-1); A11 = 174.339

 
4 0
3 years ago
Read 2 more answers
Lacey decides to take her five year old son to the history museum. The price for the child's ticket is 2.75 dollars less than th
Andrei [34K]
If the price for the adult ticket is $2.75 more than the child ticket, the adult ticket would be x + $2.75
3 0
4 years ago
2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
Oksana_A [137]

Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
4 years ago
#4.... i have no idea what to do for this
Stells [14]
<span>Perpendicular bisector is a<span> line which cuts a line segment into two equal parts at 90°  </span>⇒ 
MN ⊥ BC
BM = CM</span>

6 0
4 years ago
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