Answer:
Step-by-step explanation:
(a + b + c)³ = a³ + b³ + c³ + 3a²b + 3a²c + 3ab² + 3cb² +3 ac² + 3bc² + 6abc
a = 5a ; b =y ; c = z
(5x + y + z)(5z + y + z )(5z + y +z) = (5x + y +z)³
= (5x)³ + y³ +z³ + 3(5x)²y + 3(5x)²z + 3(5x)*y² + 3*z*y² + 3*5x*z² + 3*y*z² + 6*5x*y*z
= 125x³ + y³ +z³ + 3*25x²y + 3*25x²*z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz
= 125x³ + y³ + z³ + 75x²y + 75x²z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz
I think it might be A and C
To find the circumference of a semi-circle, it would be 1/2<span> π × d. So, pi (3.14) times the diameter, 5 would be 15.7, but then we would need to multiply it by 1/2 to get the circumference for half the circle, and that will get you 7.85. Now you can add all the lengths now. 7.85 + 7 + 5 + 7 = 26.85. Hope this helps! Let me know if you still don't get it. <3</span>
Parallel = same slope
Use formula: y = mx + b
Plug in the values (solve for b)
y = 3/2x + b
6 = 3/2(0) + b, b = 6
Solution: y = 3/2x + 6
Answer:
12.6 cm
Step-by-step explanation:
Given:
m<AOB = θ = 120°
Diameter (d) = 12 cm
Required:
Length of arc AB
Solution:
Length of arc AB = θ/360 × πd
Plug in the values
Length of arc AB = 120/360 × π×12
≈ 12.6 cm (nearest tenth)
