Answer:

Step-by-step explanation:
<u>Given: </u>
line y=3x-1
point (-3,0)
<u>Write:</u> equation of the line that is perpendicular to the given and passes through the point (-3,0)
<u>Solution:</u>
The slope of the given line is 
If
is the slope of perpendicular line, then

So, the equation of the needed line is 
Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:

<u>Answer:</u>
The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.
<u>Solution:</u>
Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)
We have to find the line equation which is perpendicular to above given line and passing through the given point.
Now, let us find the slope of the given line equation.

We know that, <em>product of slopes of perpendicular lines is -1.
</em>
So, 1
slope of perpendicular line = -1
slope of perpendicular line = -1
Now let us write point slope form for our required line.

y – (-2) = -1(x – (-3))
y + 2 = -1(x + 3)
y + 2 = -x – 3
x + y + 2 + 3 = 0
x + y + 5 = 0
y = -x -5
Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.
Answer:
5/1 or 5:1
Step-by-step explanation:
The sequence:
a 1 = 30, a 2 = 70, a 3 = 110, a 4 = 150, a 5 = 190,...
a 2 = a 1 + d
70 = 30 + d
d = 70 - 30 = 40
a n = a 1 + ( n - 1 ) * d
For the 25th month:
a 25 = 30 + 24 * 40 = 30 + 960 = 990
Answer: B ) 990.