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ArbitrLikvidat [17]
3 years ago
14

Please help will I will give brainliest to whoever explains step by step

Mathematics
1 answer:
Marat540 [252]3 years ago
7 0

Answer:

\frac{2 \:a}{h }  - b

Step-by-step explanation:

thats it but the a is capital

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Misty wishes to obtain 85 ounces of a 40% acid solution by combining a 72% acid solution with a 25% acid solution. How much of e
Y_Kistochka [10]

13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed

<u>Step-by-step explanation:</u>

Total mass of acid required= 85 ounces

Let the mass of 72% acid be 'a'

Let the mass of 25% acid be 'b'

a + b = 85

b = 85-a

85(40/100) = a(72/100) + b(25/100)

85(2/5) = a(72/100) +(85- a) (25/100)

34 = (72a/100) + (2125/100) - (25a/100)

34 - (2125/100) = (72a + 25a) /100

(3400-2125)/100 = 97a /100

97a = 1275

a =  13.15 ounces

b = 85 - 13.14

b = 71.85 ounces

13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed

4 0
3 years ago
A particular automatic sprinkler system has two different types of activation devices for each 3 sprinkler head. One type has a
zmey [24]

Answer:

There is an 85% probability that the sprinkler head will be activated.

Step-by-step explanation:

We have these following probabilities:

50% of the first sprinkler being triggered

90% of the first sprinkler being reliable

50% of the second sprinkler being triggered

80% of the second sprinkler being reliable.

What is the probability that the sprinkler head will be activated?

P = P_{1} + P_{2}

P_{1} is the probability of the first sprinkler being triggered and activated. So:

P_{1} = 0.5*0.9 = 0.45

P_{2} is the probability of the second sprinkler being triggered and activated. So:

P_{2} = 0.5*0.8 = 0.40

P = P_{1} + P_{2} = 0.40 + 0.45 = 0.85

There is an 85% probability that the sprinkler head will be activated.

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How to count slope on linear equasions<br>​
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Which variable is most important to the following problem?
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Answer:

$23.50

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4 years ago
) Write an expression that is equivalent to 3(7 + x).
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same question how many times...?

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2 years ago
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