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2 years ago

Find p and q, if Definition area is [3;10]

Mathematics

1 answer:

miss Akunina [59]2 years ago

5 0

$\\ \tt\longmapsto y=\sqrt{-x^2+px+q}$

Put(3,10)

$\\ \tt\longmapsto y^2=-x^2+px+q$

$\\ \tt\longmapsto 10^2=-(3^)2+3p+q$

$\\ \tt\longmapsto 100=-9+3p+q$

$\\ \tt\longmapsto 3p+q=109$

Use hit and trial method.

Let p,q be (27,28)

Apply

$\\ \tt\longmapsto 3(27)+28=81+28=109$

Verified

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1. What is the value of x?

lara31 [8.8K]

Is there any option to choose from ?

If so show them and I’ll probably be able to answer .

6 0

2 years ago

PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the

stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.

3 0

2 years ago

PLS HELP ME

Crank

Answer:

Yes it is statistical, it anticipates enough variability in responses

Step-by-step explanation:

-lukelaws

Hope I helped If I did please mark me brainliest if its wrong I am sorry!

3 0

2 years ago

Please answer -24x + 16y

Alex787 [66]

Answer:

-8(3x-2y)

Step-by-step explanation:

Factor out each number because 8 times 3 equals 24

And -2 times -8 is 16

3 0

3 years ago

Find the length of QP given Q is the midpoint of XF, PQ =2X+1, XF=7X-4, PF=X

nadezda [96]

Answer:

Therefore the length of QP = 3.4 units

Step-by-step explanation:

Given:

PQ = 2x + 1

XF = 7x - 4

PF = x

Q is the mid poimt of XF

∴ XQ = QF

QF = PQ - PF ..........( Q - F - P )

= 2x + 1 - x

∴ QF = x + 1

∴ XQ = QF = x + 1

TO Find:

QP = ?

Solution:

By Addition Property we have

$XP = XQ + QF+PF ..........(X-Q-F-P)\\\\$

$XF + PF =XQ + QF+PF ..........(X-Q-F-P)\\$

Substituting the given values in above equation we get

(7x - 4) + x = (x +1) + (x +1) + x

8x -4 = 3x +2

8x - 3x + 4 + 2

5x = 6

∴ $x = \frac{6}{5}$

Now we require

QP = (2x + 1)

∴ $QP = 2\times \frac{6}{5} +1\\\\QP = \frac{12+5}{5} \\\\QP =\frac{17}{5} \\\\\therefore QP = 3.4\ unit$

Therefore the length of QP = 3.4 units

3 0

2 years ago