This question is incomplete because it was not written properly
Complete Question
A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)
a) 20%
b) 40%
c) 60%
d) 75%
Answer:
d) 75%
Step-by-step explanation:
We would be solving this question using conditional probability.
Let us represent the percentage of those who passed the first quiz as A = 80%
and
Those who passed the first quiz as B = unknown
Those who passed the first and second quiz as A and B = 60%
The formula for conditional probability is given as
P(B|A) = P(A and B) / P(A)
Where,
P(B|A) = the percent of those who passed the first one passed the second
Hence,
P(B|A) = 60/80
= 0.75
In percent form, 0.75 × 100 = 75%
Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.
Some examples of perpendicular lines are the Interstate how it runs side by side with a median in the middle the roads are perpendicular because a lot of them will cross one another in a sharp turn trust me I know, Some more are the studs in the walls of your house, the wheels on your truck, the frame rails on your go cart just look around you if the lines intersect at a right angle then there perpendicular.
answer:
mean: 15.8
median: 12
mode: no mode
range: 27
step-by-step explanation:
- first know how to find each of the above and what they are
- mean = (avg) add all the numbers, then divide by the number of numbers
- median = the middle number from increasing order
- mode = the one that repeats the most
- range = the difference between the largest and smallest number
8, 35, 10, 12, 14
<u>mean</u>
8 + 35 + 10 + 12 + 14 = 79
79 / 5 = 15.8
<u>median</u>
- put them from smallest to largest
8, 10, 12, 14, 35
- 12 is the median OR the middle number
<u>mode</u>
- no number repeat, so no mode
<u>range</u>
35 - 8 = 27
Answer:
(a) See attachment for tree diagram
(b) 24 possible outcomes
Step-by-step explanation:
Given
Solving (a): A possibility tree
If urn 1 is selected, the following selection exists:
![B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]](https://tex.z-dn.net/?f=B_1%20%5Cto%20%5BR_1%2C%20R_2%2C%20R_3%5D%3B%20R_1%20%5Cto%20%5BB_1%2C%20R_2%2C%20R_3%5D%3B%20R_2%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_3%5D%3B%20R_3%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_2%5D)
If urn 2 is selected, the following selection exists:
![B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]](https://tex.z-dn.net/?f=B_2%20%5Cto%20%5BB_3%2C%20R_4%2C%20R_5%5D%3B%20B_3%20%5Cto%20%5BB_2%2C%20R_4%2C%20R_5%5D%3B%20R_4%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_5%5D%3B%20R_5%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_4%5D)
<em>See attachment for possibility tree</em>
Solving (b): The total number of outcome
<u>For urn 1</u>
There are 4 balls in urn 1
Each of the balls has 3 subsets. i.e.
So, the selection is:
<u>For urn 2</u>
There are 4 balls in urn 2
Each of the balls has 3 subsets. i.e.
So, the selection is:
Total number of outcomes is:
First you subtract 25 from 5 which equals 20 then you multipliy 4 to 20 and you get 80...so 80 is your solution.
