Answer:
The inverse will be:
Step-by-step explanation:
In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :
Now solve for y'.
First add 4 in both sides of the equation and change to the left y'.
= x + 4
Second divide by 9
/9 = (x + 4)/9
= (x + 4)/9
Now you will have to clear y, with the square root.
![[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}](https://tex.z-dn.net/?f=%5Btex%5Dy%27%5E%7B%5Cfrac%7B2%7D%7B2%7D%7D%20%3D%20%5Csqrt%7Bx%20%2B%204%7D%20%20%2F%20%5Csqrt%7B9%7D)
[/tex] =
Simplifying terms
You can check the answer by doing the evaluation of the following equation:
(f o 
) (x)
substitute the equation for y' or inverse function
f(
)
Now substitue the value into f(x)
You will have
=x
Answer:
1)49
2)231
Step-by-step explanation:
1)
4+9=13
4*2=8
8+1=9
2)
2+3+1=6
2+1=3
1*2=2
F - for simplification - we assume the orbits are circular (which they approximately are), we have a centrifugal force of <span><span>m<span><span>v2</span>R</span></span><span>m<span><span>v2</span>R</span></span></span><span>, where </span>m<span> is the mass of the planet, </span>v<span> its speed, and </span>R<span> the distance from the (center of the) sun. This force must be equal to the centripetal force, which comes from the sun's attraction, and it is </span><span><span>mG<span>M<span>R2</span></span></span><span>mG<span>M<span>R2</span></span></span></span><span>. Here, </span>M<span> is the mass of the sun, and </span>G<span> is a constant. We don't care about the actual numbers, so we write </span>C<span> be the product </span>MG<span> and observe that it is a constant independent of the orbit. These forces have to cancel out, so we have </span><span><span><span>v2</span>R=C<span>R<span>−2</span></span></span><span><span>v2</span>R=C<span>R<span>−2</span></span></span></span><span>, or </span><span><span><span>v2</span>=C<span>R<span>−3</span></span></span><span><span>v2</span>=C<span>R<span>−3</span></span></span></span><span>, so we have that the speed is proportional to </span><span><span>R<span><span>−3</span>2</span></span><span>R<span><span>−3</span>2</span></span></span><span>. Which means that if you decrease the distance to the sun, the speed goes up.</span>
So to find the answer you need to use SOHCAHTOA
Sine= Opposite/ Adjacent
Cosine= Adjacent/Hypotenuse
Tan = opposite/adjacent
angle ADC is 60 so to find the length of line ABC we would use the angle and the line DC.
We would use Tan with opposite over adjacent
Tan 60 = opp. / 5 root 3
opp. = 15
so that is the length of the entire thing, all you need to do now is find the length of the single line of BC which we can use the same equation with just Tan 30 now.
Tan 30 = opp. / 5 root 3
opp. = 5
next you need to take the entire ABC length and subtract the length of BC to get AB
15-5 = 10
so the answer would be C
