Somebody help please!!

Help! Given that tanθ=-1, what is the value of secθ, for 3π/2<θ<2π?

user100 [1]

Answer: Choice B) $\sqrt{2}$

Work Shown:

$\sec^2(\theta) = \tan^2(\theta) + 1\\\\\sec^2(\theta) = (\tan(\theta))^2 + 1\\\\\sec^2(\theta) = (-1)^2 + 1\\\\\sec^2(\theta) = 2\\\\\sec(\theta) = \sqrt{2}\\\\$

Note: secant is positive in quadrant Q4, when theta is between 3pi/2 radians and 2pi radians (270 degrees and 360 degrees). So that's why we don't consider the minus form of the plus minus.

5 0

2 years ago

Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the cir

FromTheMoon [43]

The statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Given the equation of circle be $x^{2} +y^{2}-2x-8=0$ .

We are required to find the appropriate statements related to the equation $x^{2} +y^{2}-2x-8=0$ .

$x^{2} +y^{2}-2x-8=0$ can be written as under:

$x^{2} +y^{2} -2x+1-9=0$

$x^{2} +1^{2}-2x+y^{2} -9=0$

$(x-1)^{2}+y^{2}$ -9=0

$(x-1)^{2} +y^{2} =9$

$(x-1)^{2}+y^{2} =3^{2}$

Equation of a circle usually in the form $x^{2} +y^{2} =a^{2}$ in which a is radius.

From the comparison of both the equations we get that radius is 3 units.

From the equation point will be (1,0). It is on the x axis.

Hence the statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Learn more about radius at brainly.com/question/24375372

#SPJ1

3 0

1 year ago

1 2 3 4 5 6 7 8 9 10

daser333 [38]

<h3>Answer:</h3>

2.25

<h3>Explanation:</h3>

Consider the square ...

... (x+a)² = x² +2ax +a²

The constant term (a²) is the square of half the x-coefficient: a² = (2a/2)².

The x-coefficient in your expression is 3. The square of half that is ...

... (3/2)² = 9/4 = 2.25

Adding 2.25 to both sides gives ...

... x² +3x + 2.25 = 6 + 2.25

... (x +1.5)² = 8.25 . . . . completed square

4 0

3 years ago

1. Write a numerical expression for the phrase “twelve groups of the sum of fourteen and 10.”

Rom4ik [11]

The expression for five groups of a number added to seventeen.

Let the number be X
Five groups of the number will be 5X
The required expression will be
5(X) +17

6 0

3 years ago

Is 14/35 and 21/42 proportional

PIT_PIT [208]

1.Simplified each one
2/5 (both divided by 7) , 1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10 , (1/2)*(5/5)=5/10
Now the dominators are the same ,you can just compare the numerators. It is 4:5

8 0

3 years ago