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Rasek [7]
2 years ago
12

Can someone please help me on these two?

Mathematics
1 answer:
stellarik [79]2 years ago
5 0

Answer:

Guided Practice 4:  QR = 7.12

Guided Practice 5:  x = 15

Step-by-step explanation:

<u>Guided Practice 4:</u><u> </u>

Given that:

PR = 13 \frac{3}{4} ft = 13.75 ft

PQ = 6\frac{5}{8} ft = 6.63ft

QR = ?

PQ + QR = PR

6.63 + QR = 13.75

Subtract 6.63 from both sides of the equation to solve for QR:

6.63 - 6.63 + QR = 13.75 - 6.63

QR = 7.12

Check if QR is valid:

PQ + QR = PR

6.63 + 7.12 = 13.75

13.75 = 13.75  (true statement).

<u>Guided Practice 5</u>:  

Given that:

AC = 4x - 12

AB = x

BC = 2x + 3

AB + BC = AC

x + (2x + 3) = 4x - 12

Combine like terms:

3x + 3 = 4x - 12

Add 12 on both sides of the equation:

3x + 3 + 12 = 4x - 12 + 12

3x + 15 = 4x

Subtract 3x from both sides of the equation:

3x - 3x + 15 = 4x - 3x

15 = x

Check if AB = x is valid by plugging in 15 to x values in the equation:

AB + BC = AC

15 + 2(15) + 3 = 4(15) - 12

15 + 30 + 3 = 60 - 12

48 = 48  (True statement)

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Anyone mind taking a bit of their time to help me? I’d appreciate it. Ty!
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