Can someone please help me on these two?
1 answer:
Answer:
Guided Practice 4: QR = 7.12
Guided Practice 5: x = 15
Step-by-step explanation:
<u>Guided Practice 4:</u><u> </u>
Given that:
PR =
PQ =
QR = ?
PQ + QR = PR
6.63 + QR = 13.75
Subtract 6.63 from both sides of the equation to solve for QR:
6.63 - 6.63 + QR = 13.75 - 6.63
QR = 7.12
Check if QR is valid:
PQ + QR = PR
6.63 + 7.12 = 13.75
13.75 = 13.75 (true statement).
<u>Guided Practice 5</u>:
Given that:
AC = 4x - 12
AB = x
BC = 2x + 3
AB + BC = AC
x + (2x + 3) = 4x - 12
Combine like terms:
3x + 3 = 4x - 12
Add 12 on both sides of the equation:
3x + 3 + 12 = 4x - 12 + 12
3x + 15 = 4x
Subtract 3x from both sides of the equation:
3x - 3x + 15 = 4x - 3x
15 = x
Check if AB = x is valid by plugging in 15 to x values in the equation:
AB + BC = AC
15 + 2(15) + 3 = 4(15) - 12
15 + 30 + 3 = 60 - 12
48 = 48 (True statement)
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Answer:
The linear equation for Shana's elevation is .
Step-by-step explanation:
According to the statement, we find that Shana is climbing at constant rate in time and height as a function of time can be represented by linear function:
(Eq. 1)
Where:
- Initial height above sea level, measured in feet.
- Elevation above sea level, measured in feet.
- Climbing rate, measured in feet per minute.
- Time, measured in minutes.
If we know that ,
and
. the initial height above sea level is:
The linear equation for Shana's elevation is .