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3 years ago

F(x)= (x-2)(x-3)(x-5) simplify the right side. What is the equation?

Mathematics

1 answer:

Serga [27]3 years ago

5 0

Answer:

x³ - 10x² + 31x - 30

Step-by-step explanation:

Given

(x - 2)(x - 3)(x - 5) ← expand the second pair of factors using FOIL

= (x - 2)(x² - 8x + 15) ← distribute

= x³ - 8x² + 15x - 2x² + 16x - 30 ← collect like terms

= x³ - 10x² + 31x - 30

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Sara and Sam are each working on a science project in which they need to research the individual masses of the nine planets (inc

makkiz [27]

Answer:

2000 times

Step-by-step explanation:

Given

Sara:

$Mercury = 3.302 * 10^{23$

$Saturn = 5.685 * 10^{26$

Sam:

$Mercury = 3.302 * 10^{29$

$Saturn = 5.685 * 10^{32$

To determine the number of times, the mass of Saturn is greater than the mass of Mercury, we simply do the following:

$Times = \frac{Saturn}{Mercury}$

Using Sara's measurement; this gives:

$Times = \frac{5.685 * 10^{26}}{3.302 * 10^{23}}$

Apply law of indices

$Times = \frac{5.685 * 10^{26-23}}{3.302}$

$Times = \frac{5.685 * 10^3}{3.302}$

$Times = 5.685/3.302 * 10^3$

$Times = 1.72 * 10^3$

Approximate

$Times = 2 * 10^3$

$Times = 2000$

5 0

3 years ago

The distance around a circle is called

Alex787 [66]

Circumference. :)))))

5 0

3 years ago

Read 2 more answers

A property has been assessed at $225 000. The mill rate is 14.5. To find the property tax, you would multiply the mill rate by:

jarptica [38.1K]

A would be the answer

8 0

3 years ago

During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this

alex41 [277]

Answer:

Step-by-step explanation:

Given that during the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

$\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9$

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

$\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt$

Resolve into partial fractions

$\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}$

Integrate to get

ln P -0.00474/0.0001489 (ln (0.0001489P-0.03135) = t+C

ln P -31.833 (ln (0.0001489P-0.03135) =t+C

$\frac{P}{( ( (0.0001489P-0.03135)^{31.833} } =Ae^t$

Limiting population would be infinity.

6 0

4 years ago

Which value is greater than 0.4

Maurinko [17]

Answer:

C and D

Step-by-step explanation:

9% = 9/100 = 0.09 < 0.4

0.125 < 0.4

7.8 * 100 = 780 > 0.4

7/16 = 0.4375 > 0.4

4 0

3 years ago

Read 2 more answers