The solutions or roots so-called are really just the x-intercepts, and for a quadratic equation, the vertex is found right half-way between those x-intercepts.
we can get the intercepts by zeroing out "y" or f(x), so let's take a peek at one of those,

so, the x-intercepts or solutions are at 5 and -1, let's take a peek what's the halfway point.
-1----0----1----
2 ----3-----4------5
well then, now we know the vertex is at x = 2, but, what's the y-coordinate of it anyway?
y = (x - 5)(x + 1)
y = (2 - 5)(2 + 1)
y = (-3)(3)
y =
-9
Answer:
The answer is 0
Step-by-step explanation:
3n(3m-2n) + 6m^2= (6m-3n)(2n+m)
By expansion
9mn - 6n^2 + 6m^2 = 12mn + 6m^2 -6n^2 - 3mn
By collecting like terms
9mn - 12mn + 3mn - 6n^2 + 6n^2 + 6m^2 - 6 m^2 = 0
-3mn + 3mn=0
Therefore the simplification of the expansion gives us 0
The formula of find the slope is -0.4285
use y2 - y1 over x2-x1
I think is D , hope i answer fast enough haha :D