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Citrus2011 [14]
4 years ago
9

Which of the following elements in the third period would you expect to have the most negative electron affinity value, and why?

Aluminum (Al), because it is a metal with a large atomic radius Chlorine (Cl), because it is a halogen with a high effective nuclear charge Silicon (Si), because metalloids release the most energy when gaining electrons Sodium (Na), because alkali metals only have one electron in the outer energy level
Chemistry
2 answers:
koban [17]4 years ago
6 0

The answer is: B) Chlorine (Cl), because it is a halogen with a high effective nuclear charge

Sliva [168]4 years ago
4 0

Answer:- Chlorine(Cl)

Explanations:- Electron affinity is the amount of energy released when an electron is added to an element in it's gaseous state. Electron affinity increases in a period on going left to right as the size of the element decreases and it's effective nuclear charge increases and this facilitate an element to accept the electron.

The elements mentioned here in the question belongs to the same group and out of these, chlorine is on the right most side and so it is correct choice.

Hence, Chlorine(Cl), because it is a halogen with a high effective nuclear charge is the correct choice.

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Answer:

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Explanation:

To write the complete ionic equation:

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4. indicate the correct number of each ion

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Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to
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Answer:

<u>D. It will decrease by a factor of 4</u>

Explanation:

According to the question , the equation follows :

A+B\rightarrow C+D

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Rate\ \alpha [A]^{a}[B]^{b}

r=[A]^{a}[B]^{b}.................(1)

STEP": First, find out the power "a" and "b"

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According to question, <u><em>doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,</em></u>

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

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r'=[A']^{a}[B']^{b}

Put the value of [A'] , [B'] and r' in the above equation:

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Divide equation (1) by (2) we , get

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Here A and A cancel each other

B and B cancel each other

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2= 2^{a}\times 1^{b}

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2= 2^{a}

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[B']=1/2[B]

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But

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Compare equation (a) and (b) , we get

new rate r' =

<u>r' = 1/4 r</u>

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kupik [55]
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