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3 years ago

Describe the intermolecular forces that must be overcome to convert each of the following from a liquid or solid to a gas.

Chemistry

1 answer:

kifflom [539]3 years ago

8 0

Answer:

SO₂ would require to overcome dipole-dipole bonding and London dispersion forces

H₂Se would require to overcome hydrogen-bonding

Explanation:

Both of these molecules are gaseous but are liquid under pressure

Ion-dipole bonding is present when there are ions present in the liquid. In both the cases, ions are not present hence this bonding is not present in the given molecules.

Hydrogen bonding is present in H₂Se, because there is a more electronegative element present than hydrogen. This develops partial charges on both the atoms and consequently attracts hydrogen atom of one molecule to the selenium atom of the other molecule.

London dispersion forces are present between all type of molecules, atoms and ions. These forces are weak but are dominant in molecules having large size. SO₂ is a large molecule so it will be dominant in it

Dipole-dipole bonding is present in molecules that have polar ends. SO₂ have polar ends, so this bonding will be present in it

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Vsevolod [243]

Answer:

12.01

Explanation:

(12.00*98.93% + 13*1.07%) /100% = 12.01

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3 years ago

Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma

REY [17]

Answer:

34.7mL

Explanation:

First we have to convert our grams of Zinc to moles of zinc so we can relate that number to our chemical equation.

So: 6.25g Zn x (1 mol / 65.39 g) = 0.0956 mol Zn

All that was done above was multiplying the grams of zinc by the reciprocal of zincs molar mass so our units would cancel and leave us with moles of zinc.

So now we need to go to HCl!

To do that we multiply by the molar coefficients in the chemical equation:

$\frac{0.0956g Zn}{1 } (\frac{2 mol HCl}{1molZn})$

This leaves us with 2(0.0956) = 0.1912 mol HCl

Now we use the relationship M= moles / volume , to calculate our volume

Rearranging we get that V = moles / M

Now we plug in: V = 0.1912 mol HCl / 5.50 M HCl

V= 0.0347 L

To change this to milliliters we multiply by 1000 so:

34.7 mL

7 0

4 years ago

Hello please help me on this problem thanks.sc

Sedbober [7]

The second answer, 80 J

3 0

3 years ago

On hot days, you may have noticed potato chip bags seem to inflate, even though they have not been opened. If I have a 250 mL ba

MrRa [10]

The first law here is Charles's law and the new volume will be 285.08 mL

Converting degree celsius to kelvin when solving gas laws problem.

kelvin = degree celsius + 273.15

Kelvin = 19 + 273.15 = 292.15 K

Kelvin = 60 + 273.15 = 333.15 K

Given Data:

V1 (initital volume) = 250 ml

T1 (initial temperature) = 19°c or 292.15 K

V2 (final volume) = unknwon ?

T2 (final temperature) = 60°c or 333.15 K

Charles' law which states that volume is directly proportional to temperature when the amount and pressure of the gas are constant.

Applying the formula, we get

V2 = V1T2 / T1

= 250 ml × 333.15 K / 292.15 K (cancel kelvin unit)

= 83287.5 ml / 292.15

= 285.08 ml

The new volume will be 285.08 ml

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1 year ago

Predict the sign of ΔSsys for each process: (b) A solid explosive converts to a gas.

Goryan [66]

The sign of ΔSsys for a solid explosive converts to a gas is positive.

The term used for the measurement of randomness and disorderliness in a system is known as Entropy (S). ΔS calculates the change in entropy and it is positive when entropy increase and negative when entropy decreases.

Entropy increases when heat is added to the system. Addition of heat increases the randomness of the molecules and hence the entropy increases.

When a solid explosive converts to a gas the randomness increases. Explosive causes heat and the solid is converted into gas. The randomness of molecules is maximum in gases thus the entropy increases. The sign of ΔS is positive for this process.

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2 years ago