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asambeis [7]
3 years ago
8

Match each rational expression to its simplest form. 2m2 - 4m 2(m-2) m2 - 2m +1 m - 1 m2 - 3m + 2 m2 - m m2 - m - 2 m2 - 1

Mathematics
1 answer:
mariarad [96]3 years ago
8 0

Answer:

3m + 3

Step-by-step explanation:

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A yogurt company claims that it prints a free yogurt coupon under a randomly selected 20% of its lids. A loyal customer purchase
Alona [7]

Answer:

The customer can conclude that the company's claim is correct

Step-by-step explanation:

The percentage of lids that has a free yogurt coupon = 20%

The number of cups a loyal customer purchases = 85 yogurt cups

The number of cups that contained a coupon = 12 (14.1%)

The confidence interval performed = 99% confidence interval for the proportion of yogurt cups containing coupon codes

The interval obtained = (0.044, 0.238)

Therefore, the range of proportion within which the true proportion exists is 0.044 < \hat p < 0.238

The range of percentage within which the true percentage exist is therefore;

0.044 × 100 = 4.4%  < \hat p × 100 < 0.238 × 100 = 23.8%

Given that the possible true percentage of lids that has a coupon is between 4.4% and 23.8% at 99% confidence level, the customer can conclude that only 12 of his yogurt cup contained coupon by chance and that the company's claim is correct.

4 0
3 years ago
((sinB)/1+cosB) + ((1+cosB)/sinB) = 2cscB prove that the equation is an identity
Contact [7]

Step-by-step explanation:

If you need any explanation, we can communicate normally

4 0
2 years ago
The solution set for <br> 6a^2-a-5=0
Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

a=6

b=-1

c=-5

Find two numbers that multiply to be a*c and add to be b.

a*c=-30                                   =-6(5)

b=-1                                          =-6+5

So replace -a with -6a+5a in the expression we started with

6a^2-6a+5a-5

now we factor by grouping

6a(a-1)+5(a-1)

(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

4 0
3 years ago
Overview
Alisiya [41]

Answer:

125.4

Step-by-step explanation:

Given

Number = 125.3546

Required

Round to 1 decimal place

Up till the first decimal place, the number is:

Number = 125.3

The digit after .3 is 5

The conditions for approximation are:

  • If n > 4, approximate to 1
  • Else: approximate to 0

In this case: 5 > 4, so we approximate to 1

Add this "1" to the last digit of 125.3. This becomes 125.4

<em>Hence: when the number is approximated to 1 decimal place, the digit is 125.4</em>

7 0
3 years ago
An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo
Andrew [12]
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.

Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.

Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7 

Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18

Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.

Answer: 37,39,41,43

8 0
3 years ago
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