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Fed [463]
2 years ago
14

May someone please help me

Mathematics
1 answer:
wel2 years ago
4 0

Answer:

ok but helppp meeeee nothinggggg

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Plz help one question​
Vladimir [108]

z° = 80° (Being corresponding angles)

y° + 80° = 180° (Being linear pair of angles)

=> y° = 180° - 80°

=> y° = 100°

x° = y° (Being interior opposite angles)

=> x° = 100°

3 0
2 years ago
Please help me and fast
umka21 [38]
The answer is 17.3 :)
7 0
3 years ago
Robbie owns 15 % more movies than Rebecca, and Rebecca owns 10 % more movies than Joshua. If Rebecca owns 220 movies, how many m
sammy [17]

Step-by-step explanation:

Robbie=

15%/100%=220

=33 movies

Rebecca=

10%/100%=220

11 movies

Robbie have 33 movies and Joshua have 11 movies

Thank you

Hope it helps.

4 0
2 years ago
How do I get it (it’s worth 3 marks)
Stella [2.4K]

Answer:

58.5

Step-by-step explanation:

6.5*9=58.5

3 0
2 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
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