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4 years ago

The fictitious state of Aribraska has a graduated state income tax.

Mathematics

2 answers:

pogonyaev4 years ago

8 0

Answer:

for income 15,000 is less than or equal to x is less than or equal to 40,000.

SO B

Step-by-step explanation:

just did the assignment for e2020 im 100% sure

earnstyle [38]4 years ago

7 0

Answer:

Your answer choice is correct: the range 15,000–40,000

Step-by-step explanation:

Above income of 15,000 and below income of 40,000, the problem statement tells us the tax rate is 5%. If income amount is represented by x, then .05x is the amount of the tax (subject to the credits offered by the graduated scale). The term 0.05x in the question tells you the applicable range is 15,000 ≤ x ≤ 40,000.

If 15,000 were taxed at the 5% rate, the tax amount would be $750. Instead, the tax amount on that income is 3% of 15,000, or $450—a tax that is $300 less than 0.05x. Hence in the range 15,000–40,000, the tax computation is ...

... f(x) = 0.05x -300 . . . . . for 15,000 ≤ x ≤ 40,000

_____

Above 40,000

At the middle income tax rate, $40,000 would have a tax of ...

... 0.05×40000 -300 = 1700

At 7%, $40,000 would have a tax of

... 0.07×40000 = 2800

Then the actual tax on amounts above $40,000 is $1100 less than 7% of the income.

... f(x) = 0.07x -1100 . . . . . for x ≥ 40,000

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Step-by-step explanation:

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3 years ago

PLEASE HELP!! brainliest and 40 points for the CORRECT answer

Rasek [7]

Choice C is correct

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3 years ago

The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

5 0

3 years ago

A stock trading company charges a commission of $10 per trade plus $0.025 per dollar value of stock traded. If your commission i

pickupchik [31]

Answer:

Value of the stock traded was $5200.

Step-by-step explanation:

In this question it is given that trading company charges commission of $10 per trade or transaction plus $.025 per dollar value of stock.We have to calculate the value of stock we traded if total commission (commission on trade value + commission on trade) is $140.

Let the value of stock traded was $x.

Then commission on value of the stock = x×.025

Commission on transaction = $10

Total commission = 140 = ( .025x + 10)

⇒.025x = 140-10 = 130

x = 130÷.025 = $5200

So the value of the stock = $5200

4 0

3 years ago

Read 2 more answers