Answer:
after Transcription DNA is copied into a new molecule of messenger RNA. DNA safely and stably stores genetic material in the nuclei of cells as a reference, or template.
Explanation: happy to help :)
Answer:
b.Their cell walls have very different biochemical properties.
Explanation:
Cellulose is a homopolysaccharide of glucose residues and is the main chemical component of the cell walls of the plant cells. The glucose residues in cellulose are linked together by beta 1-4 glycosidic bonds. Chitin is a linear homopolysaccharide of glucose residues and is the main structural component of the fungal cell wall. On the other hand, peptidoglycan is the major structural component of the bacterial cell walls. Peptidoglycan is a heteropolysaccharide of two different residues. These are N-acetylglucosamine and N-acetylmuramic acid. Therefore, the chemical components and that make the cell walls in plants, fungi and bacteria differ significantly from each other imparting them distinct chemical features.
The palisade cells are the main site of photosynthesis, as they have many more chloroplasts than spongy mesophyll, and also have several adaptations to maximizes photosynthesis efficiency. Large Vacuole restricts chloroplasts to a later near outside of the cell where they can be reached by light more easily.
Answer:
0.0556 mL of 90 M HCl would be taken and 9.944 mL distilled water added to make 0.5 M, 10 mL HCl solution.
Explanation:
From the dilution equation:
<em>Initial molarity (m1) x initial volume (v1) = final molarity (m2) x final volume (v2).</em>
In this case, m1 = 90 M, v1 = ?, m2 = 0.5 M, and v2 = 10 mL
v1 = m2 x v2/ m1 = 0.5 x 0.01/90 = 0.0000556 L
v1 = 0.0556 mL
This means that the initial volume of 90 M HCl to be taken is 0.0556 mL. Since the final volume to be prepared is 10 mL,
10 - 0.0556 = 9.944 mL
<em>Hence, 0.0556 mL of 90 M HCl would be taken and 9.944 mL distilled water added to make 0.5 M, 10 mL HCl solution.</em>
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H, G, E, F, And A
Hope that helped sorry if it’s wrong
