Answer: The value of for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.
Its solubility product will be as follows.
Cell reaction for this equation is as follows.
Reduction half-reaction: ,
Oxidation half-reaction: , = ?
Cell reaction:
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product,
=
Therefore, according to the Nernst equation
At equilibrium, = 0.00 V
Putting the given values into the above formula as follows.
=
= 0.577 V
Hence, we will calculate the standard cell potential as follows.
= 0.222 V
Thus, we can conclude that value of for the half-cell reaction is 0.222 V.
It’s either not testable since hypothesis need to be able to be tested or it could be not likely tho second option it has been poorly written
The total weight of both objects : 7.035 x 10⁻⁸ kg
<h3>Further explanation</h3>
Given
The weight of a grain of sand : 3.5 x 10⁻¹⁰ kg
The weight of one hair from his eyebrow : 7 x 10⁻⁸ kg
Required
The total weight of both objects
Solution
Scientific Notation consists of 2 parts
1. the first part: the first digit followed by the decimal point
2. The second part: the power of 10 (the exponents).which shows the number of digits after the decimal point
To add/subtract, the exponents must be the same and then add/subtract the coefficient
- convert the largest exponent (7 x 10⁻⁸)
7 x 10⁻⁸ = 700 x 10⁻¹⁰
Answer:
cm^3 —> dm^3
divide by 1000
159.5 — Mr of CuSO4
n (moles in mol) = c (concentration in mol/dm^3) * v (volume in dm^3)
0.100 mol of CuSO4 dissolved in 0.5dm^3 of water
calculate for mass of CuSO4 dissolved in 0.03dm^3 (30cm^3) of the solution
n = m/Mr
m = n*Mr
if 0.1 mol is dissolved in 0.5 dm^3 of water
0.5/0.03 ≈ 16.66666667
0.1 = 0.05
0.1 / 16.66666667 = 0.006
0.5 / 16.66666667 = 0.03
0.006 (mol of CuSO4) = 0.03 (dm^3 solution)
0.006 * 159.5 = 0.957 g
I think this is the answer
Strontium sulfide react with aqueus copper(ii) nitrate to form strontium (ii)nitrate and copper sulfide. the chemical equation is represented as follows
SrSO4(S) plus CU(NO3)2(aq) -->Sr(NO3)2(aq) PLUS CUSO4(s
the equation is balanced since both cupper and strontium have a valence of two.