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3 years ago

Help please!! Simplify the following expression. 4-11/3 divided by 4-2/3

Mathematics

1 answer:

enyata [817]3 years ago

3 0

Answer: C is the answer

Step-by-step explanation:

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Jay has 195 baseball cards, Jen has 46 more than Jay, how many more cards does Jen have than Jay? (I will give brainliest)

bogdanovich [222]

Jen has 46 more than Jay, “Jen has 46 more than Jay.” You answered your own question.

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2 years ago

Read 2 more answers

Which unit rates would be appropriate for describing the speed of cars in a race?

vodomira [7]

I would think miles per hour would be the best units to use because that is what the speedometer of a car is read in. Hope this helped! comment back with any questions you still have!

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3 years ago

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

4 years ago

The table shows the grades that science students earned on the last test. a:17 b:25 c:24 d:12 f:2 What percent of students recei

Molodets [167]

Answer:

0.525 %

Step-by-step explanation:

there is a total of 80 students and 42 received a A or B so 42/80 = 0.525

Hope this helps!

8 0

3 years ago

GEOMETRY: You are building a shelf that fits in a corner. In the figure, the entire shelf is IJK . Each unit in the coordinate p

arsen [322]

Answer:

A= 12.5 inches²

Step-by-step explanation:

a=1/2bh

a=1/2(5)5

a=1/2(25)

a= 12.5

3 0

3 years ago