What number am I?

Mathematics

1 answer:

Rudik [331]3 years ago

6 0

Answer:

Step-by-step explanation:

The first digit is 9

the 2nd one from the right = 2

So far what you have is

911, 121

941,121

There seems to be a second 4 implied. What is it? I'll edit if you get it to me in the next hour.

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Help please, this is my last question I am asking you guys, I promise <3

butalik [34]

Answer:

Part A: 1.25g + 14.25 < 55.00

Part B: 32 games

Step-by-step explanation:

price per game * games played (1.25g) + money he's already spent (14.25)

must be less than or equal to his total budget (55.00)

equation: 1.25g + 14.25 < 55.00

total (55.00) - already spent (14.25) = what he can spend on games (40.75)

55.00 - 14.25 = 40.75

arcade budget (40.75) / cost per game (1.25) = 32.6

because you can't play 0.6 games, 32 games

5 0

3 years ago

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Vanyuwa [196]

Answer:

Look at the attachment.

_____
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4 0

2 years ago

Let f(x) = 7x^2-5x+3 and g(x) = 2x^2+4x-6

Troyanec [42]

Answer:

$\large\boxed{A.\ f(x)+g(x)=9x^2-x-3}\\\boxed{B.\ f(x)-g(x)=5x^2-9x+9}\\\boxed{g(x)-f(x)=-5x^2+9x-9}$

Step-by-step explanation:

$f(x)=7x^2-5x+3,\ g(x)=2x^2+4x-6\\\\A:\\f(x)+g(x)=(7x^2-5x+3)+(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3+2x^2+4x-6\qquad\text{combine like terms}\\f(x)+g(x)=(7x^2+2x^2)+(-5x+4x)+(3-6)\\f(x)+g(x)=9x^2-x-3$

$B:\\f(x)-g(x)=(7x^2-5x+3)-(2x^2+4x-6)\\f(x)+g(x)=7x^2-5x+3-2x^2-4x+6\qquad\text{combine like terms}\\f(x)-g(x)=(7x^2-2x^2)+(-5x-4x)+(3+6)\\f(x)+g(x)=5x^2-9x+9$

$C:\\g(x)-f(x)=(2x^2+4x-6)-(7x^2-5x+3)\\g(x)-f(x)=2x^2+4x-6-7x^2+5x-3\qquad\text{combine like terms}\\g(x)-f(x)=(2x^2-7x^2)+(4x+5x)+(-6-3)\\g(x)-f(x)=-5x^2+9x-9$