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3 years ago

¿cuál es el vértice de una parábola que corta los ejes en los puntos (-1,0) , (5,0), (0,-10) ?

Mathematics

1 answer:

kvasek [131]3 years ago

3 0

Answer:

vertex: (2,-18)

Step-by-step explanation:

y = ax² + bx + c

(-1,0) : a - b + c = 0 ...(1)

(5,0) : 25a +5b +c = 0 ...(2)

(0,-10): 0a + 0b + c = -10 c=-10

(1) x5: 5a - 5b + 5c = 0 ...(3)

(2)+(3): 30a + 6c = 0 30a = -6c = 60 a = 2

(1): 2 - b -10 = 0 b = -8

Equation: y = 2x² - 8x -10 = 2 (x² -4x +4) - 18 = 2(x-2)² -18

equation: y = a(x-h)²+k (h,k): vertex

vertex: (2,-18)

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¿cuál es el vértice de una parábola que corta los ejes en los puntos (-1,0) , (5,0), (0,-10) ?​

¿cuál es el vértice de una parábola que corta los ejes en los puntos (-1,0) , (5,0), (0,-10) ?