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Lapatulllka [165]
3 years ago
13

What is the equation of a circle with center (-4,7) and radius 8?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

The equation of the circle would be (x−(−4))2+(y)2=6or (x+4)2+(y−72=36.

Explanation:The equations of the circle is(−h)2+y−k)2=r2

where h is the x of the center of the circle and k is the y of the center of the circle, and r is the radius(-4,7) radus is 6h = -4k = 7r = 6plug in the values(x−(−4))2+(y−7)2=62simplify(x+4)2+(y−7)2=36.

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How do i solve this question
Artyom0805 [142]
First multiply -3 to -5/3. Giving you -14=5+b. Then subtract 5 from both sides to isolate b. -14+5= -9 so b=-9 which is your y-intercept
5 0
3 years ago
Telephone plan consist of a monthly fee of $20 plus $.20 per minute for long distance calls made write an equation for the total
HACTEHA [7]

Answer:

C=20+0.20N

Step-by-step explanation:

Fixed monthly fee = $20

Amount charged per minute for long distance calls = $0.20

C denotes total cost such that N minutes are used for long distance calls.

Amount charged for N minutes for long distance calls =0.20N

Therefore, an equation for the total cost, C, when N minutes are used for long distance calls is C=20+0.20N

5 0
3 years ago
Can you please Help!!!! 20 points!!!!!!
Mademuasel [1]

Answer:

I'm doing the same thing and, I don't understand it either.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can someone help me? I need question #23
weqwewe [10]

Answer:

x = 3; y = 11

Step-by-step explanation:

A parallelogram has two pairs of congruent opposite sides. For quadrilateral ABCD to be a parallelogram, sides AB and CD must be congruent, and sides AD and BC must be congruent.

AB = CD

2y + 2 = 3y - 9

-y = -11

y = 11

AD = BC

3x + 6 = y + 4

We already know y = 11, so we substitute 11 for y.

3x + 6 = 11 + 4

3x + 6 = 15

3x = 9

x = 3

Answer: x = 3; y = 11

8 0
3 years ago
For the function f(x)=3xsquared- 2x+5 find f(1) f(-2) and f(a)
Oksanka [162]
f(x)=3x^2-2x+5\\\\
f(1):\ \ Substitude\ 1 \ as\ x\ into\ function:\\
f(1)=3*1^2-2*1+5=3-2+5=\textbf{6}\\\\
f(-2)\ \ Substitude\ x=-2\\
f(-2)=3*(-2)^2-2*(-2)+5=3*4+4+5=12+4+5=\textbf{21}\\\\
f(a)\ \ substitude\ x=a\\
f(a)=\underline{3a^2-2a+5}
4 0
3 years ago
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