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3 years ago

What is the equation of a circle with center (-4,7) and radius 8?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

6 0

The equation of the circle would be (x−(−4))2+(y)2=6or (x+4)2+(y−72=36.

Explanation:The equations of the circle is(−h)2+y−k)2=r2

where h is the x of the center of the circle and k is the y of the center of the circle, and r is the radius(-4,7) radus is 6h = -4k = 7r = 6plug in the values(x−(−4))2+(y−7)2=62simplify(x+4)2+(y−7)2=36.

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What is the volume of three cubes, each with a side length of 1/3 foot? V = s3, where s is the side length.

marta [7]

1/3 of a foot = 4 inches
(4^3)*3=
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(16*4)*3=
64*3=
192

8 0

3 years ago

Five whole numbers are written in order

jeka57 [31]

Answer:

x=7

y=8

Step-by-step explanation:

-Given that the mean and median is the same.

-Let b=mean =median

#Given that the set is arranged in order and is even:

$median=\frac{n+1}{2}\\\\Median=3^{rd} \ term\\\\=x$

Hence:

$b=median=mean\\\\b=x\\\\\therefore mean=median=x$

-Applying the mean formula:

$\bar x=\frac{1}{n}\sum{x_i}\\\\\therefore 5x=4+6+x+y+10\\\\4x=20+y\\\\x=5+0.25y$

#Since the number are in order:

$6$

Hence, x=7 and y=8

8 0

2 years ago

Help ASAP!!!!<br> Which statement about the graph of the function y=(1/3)x are true?

mafiozo [28]

Answer:

Step-by-step explanation:

1) False: The function is decreasing (because the base, 1/3, is between 0 and 1).

2) True: The function is decreasing (see #1, above)

3) False: There is no x-intercept.

4) True: If x is 0, then y = (1/3)^0 = 1.

5) False: the range consists of the set of all real numbers greater than zero.

7 0

3 years ago

Read 2 more answers

Help me pleaseeeeeeeeee

crimeas [40]

Answer:

x=10 and x=-9

Step-by-step explanation:

Factor:

(x-10)(x+9)=0

x-10=0

x=10

and

x+9=0

x=-9

3 0

2 years ago

The sum of squares of two consecutive odd numbers is 514 find the numbers

amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

$\rule{130}1$

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

$\rule{130}1$

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup$

When,

$\bullet\: \textsf {x = } \textbf {15}$

$\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}$

$\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.$

5 0

3 years ago