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iris [78.8K]
3 years ago
5

PLSS HELP Identify the five important values from this box and whisker plot. Explain how you got your answers

Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

46, 55, 58, 63, and 66

Step-by-step explanation:

These points are where each line is at, beginning marked at 46, next line at 55, next at 58, next 63, and ends at 66.

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Pleaseeee help me ASAP!
faust18 [17]

Looks good to me!! Yuh done good.

8 0
3 years ago
The perimeter of a right triangle is 30 feet and the area is 30 square feet. If the lengths of the sides of the triangle are eac
liq [111]

Answer:

300

Step-by-step explanation:

a triangle has 3 sides and so perimeter is just adding all the sides together so the perimeter is 30 that means each side is ten so multiply those all by ten as it says and then they are all 100. add them to get 300, hope this helps :)

5 0
3 years ago
In the given figure, ray OD stands on a line AOB , ray OE and OC are the angles bisector of
Dmitry_Shevchenko [17]
Ray OE is the angle bisector of angle AOD

ray oc is the bisector of angle BOD

7 0
4 years ago
11. Given: TQ bisects ZRTP, QS || PT<br> RT = 30. Find QP, RS and QS
yaroslaw [1]

QP=24 cm

RS=11.25 cm

QS=18.75 cm

<u>Explanation</u>:

Given that TQ bisects <RTP

therefore(1)

consider ΔRQS and ΔRPT

QS||PT,RP and RT are transversals

(alternate angles)(2)

comparing (1) and (2)

and triangle SQT is isocelus

Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)

Therefore <RQS=<RPT(corresponding angles)

<RSQ=<RTP(corresponding angles)

therefore by AA criterion for similarity

ΔRQS~ΔRPT

According to the property of similar triangles

RQ/RP=RS/RT=QS/PT9/RP=X/30=QS/50\\9/RP=X/30=(30-X)/50\\X/30=(30-X)/50\\50X=30(30-X)\\50X=900-30X\\50X+30X=900\\80X=900\\X=900/80=11.25\\RS=11.25 cm\\QS=30-X=30-11.25\\QS=18.75 cm\\9/RP=X/30\\9/RP=11.25/30\\9*30/11.25=RP\\RP=24 cm

3 0
3 years ago
Anyone please help me pleaseeee
lora16 [44]

R = { (x,y): 3x-y=0 }

The condition is 3x=y so that's not going to be any of these things.

R is reflexive if (x,x)∈R for all x.   Let's check.

3x - y = 3x - x = 2x ≠ 0  necessarily.   NOT REFLEXIVE

R is symmetric if (x,y)∈R → (y,x)∈R.   Let's check.

(x,y)∈R  so

3x-y = 0

y  = 3x

Is  (y,x)∈R.  That would be true if 3y-x=0

3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC

R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R.   Let's check.

3x-y = 0  so y=3x

3y-z = 0 so z=3y = 9x

3x - z = 3x - 9x = -6x ≠ 0 necessarily   NOT TRANSITIVE

6 0
3 years ago
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