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leva [86]
4 years ago
9

There are 9 performers who are to present their acts at a variety show. How many different ways are there to schedule their appe

arances
Mathematics
1 answer:
nika2105 [10]4 years ago
3 0
For this type of question it is easiest to think about it in terms of a simple multiplication. The way we can do this is by working out how many possibilities there are for each position on the program. This is as follows:
For the first act, there are 9 possible performers we can pick
For the second act, because we have already assigned a performer to the first act, there are only 8 possible performers
For the third act, because we have already assigned a performer to the first two acts, there are only 7 possible performers
This goes on and on until we reach the final act, where we have used all the performers except one.
Therefore we can say:
For the first act there are 9 possibilities
For the second act there are 8 possibilities
For the third act there are 7 possibilities
For the fourth act there are 6 possibilities and so on
If we want to write this mathematically we can just say that there are:
9 possibilities x 8 possibilites x 7 possibilities etc right down until we are at the final act where there is 1 possibility.
To write this out as an equation we just say:
9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = the number of different ways
In maths however, we have a much simpler way of saying this, which we call "factorial".
That whole stream of numbers up there can just be said to be "9 factorial", or if we are writing it in an equation "9!". You may find that your calculator has a button which has an "!" on it. If you put in the number of performers and then press the "!" button, it will give you the answer to your question.
Hope this helped you :)
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dante has been putting one peeny in his bank everyday Now he has 161 pennies Hor how many weeks has d
nikklg [1K]
All you need to do is divide 161 by 7 and get 23 weeks

6 0
3 years ago
Find the indicated conditional probability
andrezito [222]

Given:

The two way table.

To find:

The conditional probability of P(Drive to school | Senior).

Solution:

The conditional probability is defined as:

P(A|B)=\dfrac{P(A\cap B)}{P(B)}

Using this formula, we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{P(\text{Drive to school and senior})}{P(\text{Senior})}                      ...(i)

From the given two way table, we get

Drive to school and senior = 25

Senior = 25+5+5

           = 35

Total = 2+25+3+13+20+2+25+5+5

         = 100

Now,

P(\text{Drive to school and senior})=\dfrac{25}{100}

P(\text{Senior})=\dfrac{35}{100}

Substituting these values in (i), we get

P(\text{Drive to school }|\text{ Senior})=\dfrac{\dfrac{25}{100}}{\dfrac{35}{100}}

P(\text{Drive to school }|\text{ Senior})=\dfrac{25}{35}

P(\text{Drive to school }|\text{ Senior})=0.7142857

P(\text{Drive to school }|\text{ Senior})\approx 0.71

Therefore, the required conditional probability is 0.71.

5 0
3 years ago
Read 2 more answers
One-fifth of a number x is less than 8. Find the greatest possible prime number x.
GuDViN [60]
Hello there, I am unable to use the “less than” symbol. Sorry :( .

1/5x "less than" 8
x “Less than” 40

Prime number is 37,41.
Therefore x is 37.
8 0
2 years ago
Find m. Please guys I really need your help :(
vredina [299]

Answer:

m=\sqrt{2} inches

Step-by-step explanation:

From the diagram, it is given that the triangle is a right angle isosceles triangle (angles are 45°, 45° and 90°). This means that the two shorter sides of the triangle are equal in length and that the side m can be found by using the Pythagorean theorem a^{2}+b^{2}=c^{2}.

m^{2}+m^{2}=2^{2} (The two shorter sides of the triangle are equivalent)

2m^{2}=4

m^{2}=2

m=\sqrt{2} inches

I hope this helps :)

8 0
3 years ago
Please show x < 80 on a number line
nevsk [136]

Answer:

on the number line make an open circle at 80 (am open circle is this: ○) and connect that to an arrow that points back to 0 and the negative numbers. It doesn't matter how far back as long as you make it an arrow

7 0
3 years ago
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