Hi again!
2x - y = 80
5y = x
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We need to solve 2x - y = 80 for y
2x - y = 80
-y = 80 - 2x
Multiply both sides by -1 because y cannot be negative
-y * -1 = -1(80 - 2x)
y = 2x - 80
Now we can substitute 2x - 80 for y in 5y = x
5y = x
5(2x - 80) = x
Use the distributive property
(5)(2x) + (5)(-80) = x
10x - 400 = x
Add -x on both sides
10x - 400 - x = x - x
9x - 400 = 0
Add 400 on both sides
9x - 400 + 400 = 0 + 400
9x = 400
Divide both sides by 9
9x/9 = 400/9
x = 400/9
To find y, we can substitute 400/9 for x in y = 2x - 80
y = 2x - 80
y = 2(400/9) - 80
y = 800/9 - 80
y = 800/9 - 80/1
y = 800/9 + -720/9
y = (800 - 720)/9
y = 80/9
Thus,
The answers are: y = 80/9 and x = 400/9
As always, it is my pleasure to help students like you
The number of 11-inch softball is 70 and the number of 12-inch softball is 50.
<u>Step-by-step explanation</u>:
<u>Given that,</u>
- The cost of 11-inch softball = $2.50
- The cost of 12-inch softball = $3.50
<u>Let us assume,</u>
- The number of 11-inch softball be 'x'.
- The number of 12-inch softball be 'y'.
<u>Forming the equation to solve x and y values :</u>
- The total number of softball ordered = 120
- The total cost for 120 softballs = $350
x + y = 120 -------(1)
2.5x + 3.5y = 350 --------(2)
<u>Multiply eq(1) by 2.5 and subtract eq(2) from eq(1)</u>,
2.5x +2.5y = 300
-<u>(2.5x +3.5y = 350)</u>
<u> -1y = -50</u>
Therefore the value of y = 50.
The number of 12-inch softball is 50.
<u>Substitute y=50 in eq(1),</u>
x+50 = 120
x = 120-50
x = 70
The number of 11-inch softball is 70.
A. The theoretical probability for pink is 95/185 or about 51.35%
B. The theoretical probability for brown is 90/185 or about 47.82%.
C. To find the experimental probability, we will make another fraction. The number of outcomes will be the numerator and the total will be the denominator.
Pink 36/69 = 52.17%
Brown 33/69 = 47.82%
Answer:
7
Step-by-step explanation:
It is a pattern where you add 3 each time
Answer:
83%
Step-by-step explanation:
100% - 17% = 83%
Cutting the number of pages by 17% leaves 83% of the original number of pages.