Answer:
In inches, the radius of the can is <u>2</u>.
Step-by-step explanation:
Given:
The number of cubic inches in the volume of a 6-inch high cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.
Now, to find the radius of the can in inches.
Let the radius of can be 
Height of can = 
<em>As given, the number of cubic inches of the volume of the cylindrical can equals the number of square inches in the area of the label that covers the lateral surface of the can.</em>
<em><u>So, </u></em>
<em><u>Volume of can = lateral surface area of can.</u></em>
Now, we put formula of volume and lateral surface area of cylinder:


<em>Dividing both sides by </em>
<em> we get:</em>
<em />
<em />
<em />
<em />
<em>Dividing both sides by 6 we get:</em>

Therefore, in inches, the radius of the can is <u>2</u>.
Answer:
it would be small.
Step-by-step explanation:
bcause its the smallest one and theres only 1 softball.
Answer:
C
Step-by-step explanation:
Answer:
a)
, b)
, c) 
Step-by-step explanation:
a) We evaluate the function at
:



b) First, we determine the inverse of the function by algebraic means:
1)
Given
2)
Compatibility with addition/Associative property
3)
Existence of additive inverse/Modulative property
4)
Compatibility with multiplication/Commutative and associative properties
5)
Existence of multiplicative inverse/Modulative and commutative properties
6)
Symmetry property of equality
7)
Definitions of subtraction and division
8)
/
/Result
c) Now we evaluate the expression obtained on b) at the given number:
