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3 years ago

The question i have it number 3

Mathematics

1 answer:

viktelen [127]3 years ago

6 0

Answer:

wont load but pick 3

Step-by-step explanation:

mkk

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The youth group is going on a trip to the State Fair trip cost 63 dollars included in that price is 13 dollars for a concert tic

Marina CMI [18]

Answer:

The cost of one pass is 25$

Step-by-step explanation:

Call the cost of one of the passes, P. So we have

63 = 13 + 2P - subtract 13 from both sides

50 = 2P - divide both sides by 2

25 = P

So the cost of one pass = $25

4 0

2 years ago

Six subtracted from x is less than 25

AnnZ [28]

Answer is going to be x>-19

4 0

3 years ago

Soil sells for 8 1/4 cents per pound. How much would you save if you bought a 100- pound sack for $7.45?

asambeis [7]

Answer:

$0.80

Step-by-step explanation:

If the 100 pounds was bought separately (of course in real life you will probably not)

= 100 pounds x $0.0825/pound

= $8.25

As you can see it will cost more than if you buy a 100 pound sack.

Cost Difference = $8.25 - $7.45 = $0.80

That means you will save $0.80 from it.

4 0

2 years ago

Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv

Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$