Answer:
6/16
Step-by-step explanation:
On a 16 sided die there would be number as follows :
1,2,3,.. 16 The prime number out in this set of numbers are
2,3,5,7,11, and 13
There are 6 prime number so the probability of rolling a prime number is
6/16
X^2^4 = x^8
Just multiply then 2 and 4 to get 8
Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
Learn more about polynomial here
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P.E.M.D.A.S
First , you multiply.
200+(-16)4
200+(-64)
Since they have different signs, you subtract and keep the sign of the greater absolute value.
200+(-64)=136
