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ozzi
3 years ago
6

Factor the expression. 144*x^2 - 25

Mathematics
2 answers:
saul85 [17]3 years ago
3 0

Answer:

\hookrightarrow \: { \tt{(144 {x}^{2}  - 25)}} \:  \hookleftarrow

\dashrightarrow \: { \tt{ {12}^{2}  {x}^{2} -  {5}^{2}  }} \\  \\ \dashrightarrow \: { \tt{ {(12x)}^{2} -  {5}^{2}  }}

• from difference of two squares identity of quadratics:

{ \boxed{ \rm{( {a}^{2} -  {b}^{2} ) = (a - b)(a + b) }}}

→ a is 12x

→ b is 5

\dashrightarrow \:{ \boxed{ \boxed { \tt{(12x - 5)(12x + 5)}}}}

Mariana [72]3 years ago
3 0

Answer:

(12x + 5)(12x − 5)

Step-by-step explanation:

1. 2^4 * 3^2 * x^2 -5^2

2. (2^2 * 3x)^2 -5^2

3. (2^2 * 3x -5)(2^2 * 3x +5)

4. (4 * 3x - 5)(4 * 3x + 5)

5. (12x-5)(12x+5)

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Solve this equation. Enter your answer in the box.<br> 13(y+7)=3(y−1).
Fofino [41]

★To Solve :

\rm\blue{13(y+7) = 3(y-1)}

⠀⠀⠀⠀⠀

★SOLUTION :

\rm\red\leadsto{13(y+7) = 3(y-1)}

\rm\red\leadsto{13\times{y}+13\times7= 3\times{y}-3\times1}

\rm\red\leadsto{13y+91=3y-3}

\rm\red\leadsto{13y-3y=-3-91}

\rm\red\leadsto{10y=-94}

\rm\red\leadsto{} y =\dfrac{   { \cancel{-94}}^{ \:-45 } }{   { \cancel{10}}^{ \: 5} }

\rm\red\leadsto{y=}\dfrac{-47}{5}

____________________

5 0
3 years ago
Read 2 more answers
PLZ HELP ASAP TANGENTS OF CIRCLES PROBLEMS
quester [9]
A circumscribed angle is that which is formed by the intersection of the two tangent lines in a circle. With this, we can conclude that segments AC and AB are tangent to circle O. The tangent lines forms a right angle with the radius of the circle drawn from the center of the circle to the tangent point. 

By the explanation above, we can say that angles C and B are equal to 90° and that triangle ACO and triangle ABO are congruent. Which means that segment AC is equal to segment AB. Thus, the length of AB is also 4. 

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7 0
4 years ago
Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d​
gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

Step-by-step explanation:

Evaluate:

\dfrac{b-3a}{bc^{2}-d}

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\

\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

\dfrac{b-3a}{bc^{2}-d}=1

6 0
3 years ago
Solve for x: −2x − 4 &gt; 8<br><br> x &lt; −6<br> x &gt; −6<br> x &lt; −2<br> x &gt; −2
Yuki888 [10]

Answer:

x > -6

Step-by-step explanation:

-2x - 4 > 8

collect like terms

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Divide both sides by -2, we will have

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8 0
4 years ago
Read 2 more answers
List 5 numbers with a mean of 5
givi [52]

If their mean is 5, then the numbers add up to 25.
Here are a few sets that do the job:
 
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10, 20, 30, 40, -75

+2,  -2,  +99,  -99,  25

1,  5,  5,  5,  9

6 0
3 years ago
Read 2 more answers
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