Answer:
27 quarters and 37 nickels
Step-by-step explanation:
Nickels are 5¢
Quarters are 25¢
$8.60 is 172 nickels (860/5)
$8.60 is 34.4 quarters (860/25)
So then let's split it half-and-half.
425 and 435
425 would become 17 quarters.
435 would become 87 nickels.
This is still too much.
Now let's try 700 and 160.
700 would become 28 quarters
160 would become 32 nickels.
28+32=60.
This is a lot closer.
So now 27 quarters and 37 nickels. This works.
Answer:
The actual speed = 27.12 mi/h
Direction = 36.5° in NE(north of east)
Step-by-step explanation:
As given , A hot air balloon is flying at a constant speed of 20 mi/h at a bearing of N 36° E.
⇒θ = 36°
Let v₀ be the constant speed, then v₀ = 20
Let vₓ be the speed in East direction
be the speed in North direction
So,
vₓ = v₀ sin(θ) = 20 sin(36°) + 10 ( As given, There is a 10mi/h cross wind blowing due east.)
⇒vₓ = 20(0.588) + 10 = 11.76 + 10 = 21.76 mi/h
and
= v₀ cos(θ) = 20 cos(36°) = 20(0.809) = 16.18 mi/h
Now,
the actual speed = √(vₓ)² + (
)²
= √(21.76)² + (16.18)²
= √473.498 + 261.792
= √735.29 = 27.12
⇒The actual speed = 27.12 mi/h
Now,
Direction = θ = 
⇒ Direction = 36.5° in NE(north of east)
As for this problem, it would be best to approach this with a ratio to ratio approach. This would then involve the equation with fractions which is the common conversion from ratios to easily solve the problems concerning these. The equation then would look somehow like this:
0.01 miles / 1 hour = x miles / 2.4 hours
The easiest way would be just to multiply the numerator, which is the miles, to 2.4. So when it is multiplied to the numerator, the equation then would turn to:
0.01 miles x 2.4 / 1 hour = x miles / 2.4 hours
0.024 miles would be the answer.
Step-by-step explanation:
I hope this helps. good luck
Answer:
25π
Step-by-step explanation:
1) for whole circuit: A=π*r², where r - radius of the given circle;
2) for a quater of the circuit: A=πr²/4;
3) finally, A=π*100/4=25π.