Question

PLEASE HELP MEEEEEEEEEEEEEEEEEE

Answer 1

Perimeter of the carpet = 21.8 m

Area of the carpet = $29.4 m^{2}$

Given:

Dimension of the living room:

$l = 4.9 m\\w = 6 m$

A. Perimeter of the carpet = perimeter of a rectangle

Perimeter = $2(l + w)$

Substitute

$Perimeter = 2(4.9 + 6)\\= 21.8 m$

Perimeter of the carpet = 21.8 m (The digits here are significant)

B. Area of the carper = area of a rectangle

Area = $l \times w$

Substitute

$Area = 4.9 \times 6\\= 29.4 m^{2}$

Area of the carpet = $29.4 m^{2}$ (the digits here are significant)

Therefore, considering the rules of significant digits:

Perimeter of the carpet = 21.8 m

Area of the carpet = $29.4 m^{2}$

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