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Dahasolnce [82]
3 years ago
11

Is it faster to drive a car going 40 miles per hour or 50 feet per second?

Mathematics
2 answers:
Mrrafil [7]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

To solve this problem, let's convert these into the same units.

We use the conversions:

- 1 hour = 60 min

- 1 min = 60 sec

- 1 mile = 5280 ft

40 miles/hour = 40 miles/60 minutes = \frac{40}{60} miles/min = \frac{40}{60} miles/60 seconds =

\frac{\frac{40}{60} }{60} miles/sec = \frac{\frac{40}{60} }{60}*5280 ft/sec = 176/3 ft/sec ≈ 58.67 ft/sec

Obviously, 58.67 ft/sec > 50 ft/sec.

Thus, yes, it is faster to drive a car going 40 mph than a car going 50 ft/sec.

Hope this helps!

dalvyx [7]3 years ago
5 0

Answer:

40 miles per hour is faster.

Step-by-step explanation:

First we have to find how many feet per hour the second car is going.

There are 60 seconds in a minute, and 60 minutes in an hour.

50*60=3600

There are 3600 seconds in a hour.

50*3600=180000

This means that the second car going 180000 feet per hour.

1 mile is 5280 feet.

Now we have to figure out how many miles 180000 is.

We can do that by setting up the following expression.

180000/5280=34 1/11 or 34.09

Since 40 is greater than 34.09, it is faster to drive a car going 40 miles per hour.

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An image of a book shown on a website is 3 inches wide and 4.5 inches tall on a computer monitor. The actual book is 9 inches wi
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Answer:

It Depends

Step-by-step explanation:

If the image is the scale, the answer is 1/3, since its width of 3 is 1/3 the width of the actual book.

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3 years ago
express the numbers eight, fifteen and seventeen in base 2. I have forgotten how to do the base 2 question.
saw5 [17]
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6 0
3 years ago
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5 0
3 years ago
The height of a rocket a given number of seconds after it is released is modeled by h (t) = negative 16 t squared + 32 t + 10. W
vaieri [72.5K]

Answer:The number of seconds after rocket is released

Step-by-step explanation:

Given

The height of  a rocket after it is released is modeled by

h\left ( t\right )=-16t^2+32t+10

Here t represent the number of seconds after the rocket is released.

Initial velocity can also be determined by this equation by differentiating the h\left ( t\right ) w.r.t time

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4 0
3 years ago
Read 2 more answers
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