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Setler [38]
2 years ago
6

What is the domain of the function shown on the graph?

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
5 0

Step-by-step explanation:

The last one.

-5 is notht included but 6 is.

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The numbers of inches of snow per month in Portland, Maine, for a period of twelve months, are:
Gnom [1K]
The range is 19-0=19 so therefore your answer is C.
The range is the largest number subtracted by the smallest number.
8 0
3 years ago
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What is the length of an arc with a central angle of 23π radians and a radius of 24 cm?
dalvyx [7]
We can solve for the arc length using the formula shown below:
Arc Lenght = 2pi*r(central angle/360)

We need to convert the central angle such as:
Central angle = 23pi rad * (180°/pi rad) = 23*180
Radius = 24cm 

Solving for arc length:
Arc length = 2*3.14 *24*(23*180/360)
Arc length = 1733.28 cm

7 0
2 years ago
Write the number thirty five million thirty thousand
Shtirlitz [24]
35,030,000 is the correct answer, hope this helps.

7 0
3 years ago
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If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
Find the surface area of the right triangular prism shown below.<br><br> units^2_____________
stiks02 [169]

44

Step-by-step explanation:

find the area of the base of the shape, them boom, that's your answer!

7 0
3 years ago
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