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2 years ago

Determine the solution to the equation below x2 = 7

Mathematics

1 answer:

liberstina [14]2 years ago

6 0

Answer:

X=7/2

x=3.5

Step-by-step explanation:

Hope this helped you.. Have a nice day dear...❤️

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Rita has deposited $1000 in a bank account. At the end of each year, the bank posts interest to her account in the amount of 5%

Ierofanga [76]

$1,040 is how much you would have remaining at the end if that's what you are looking for.

3 0

3 years ago

The March utility bills (in dollars) of 30 homeowners are listed below. 44 38 41 50 36 36 43 42 49 48 35 40 37 41 43 50 45 45 39

Ulleksa [173]

Step-by-step explanation:

What we will do is create a table with the data they give us, the first thing will be to organize it from smallest to largest, like this:

33, 35, 35, 36, 36, 36, 37, 38, 38, 39, 40, 40, 41, 41, 41, 42, 42, 43, 43, 43, 44, 45, 45, 47, 48, 48, 49, 50, 50, 50

Now we know that the smallest number is 33 and the largest is 50, to create 5 ranges, we will calculate the difference and divide by 5.

(50 - 33) / 5 = 3.4

Therefore we will make ranges of 3 and 4, values, like this

Rank 1: 33 - 36

Rank 2: 37 - 39

Rank 3: 40 - 43

Rank 4: 44 - 46

Rank 5: 47 - 50

We will calculate the frequency distribution of values in each range:

Rank 1: 6

Rank 2: 4

Rank 3: 10

Rank 4: 3

Rank 5: 7

5 0

3 years ago

Which of the following integers is a perfect square? A 36 B 48 C 44 D 32

Anika [276]

Answer:

Step-by-step explanation:

since 36=6² and the other option is not square of integer

5 0

3 years ago

Read 2 more answers

At a amusement ,park 360 visitors rode the roller coaster in 3 hours.Write and solve a proportion to find the number of visitors

Pachacha [2.7K]

First you need to find out about how many people went on the roller coaster in one hour by doing 360 divided by 3 and you would get 120. So then you would try to find out how many people went on the coaster in 7 hours by doing 360 times 2 because 3 hours multiplied by 2 is 6 and you would do that to find out how many people went on the coaster in 6 hours, and you would get 720. Next, you have 1 more round of people, so you need to do 720 + 120 which is 840. So about 840 people rode the coaster in 7 hours. Hope this helped.

6 0

3 years ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

2 years ago