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3 years ago

Distance and midoint

Mathematics

1 answer:

kykrilka [37]3 years ago

6 0

What about distance and midpoint

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Factor the expression x^4 -1 using the polynomial identify x^2-y^2)=(x-y)(x+y)

Orlov [11]

Answer:

(x - 1)(x + 1)(x² + 1)

Step-by-step explanation:

Step 1: Factor Difference of Squares

(x² - 1)(x² + 1)

Step 2: Factor Difference of Squares for non-complex binomial root

(x - 1)(x + 1)(x² + 1)

And we have our answer!

3 0

3 years ago

How do you solve 32 - 6x = 53?

katrin2010 [14]

$\large\boxed{x=-\frac{7}{2}}$

To solve for $x$ , we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

$\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}$

Divide both sides of the equation by $-6$ .

$\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}$

7 0

2 years ago

Read 2 more answers

Geometry question please help

Licemer1 [7]

Answer:

BE=AD

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help me plz and thx :)

ikadub [295]

Answer:

I am sure it is false. becuase a dependent variable is something you measure and you have to count the eggs.

4 0

2 years ago

How to find the number of sides of a polygon when given the interior angle sum

wariber [46]

Given:

Sum of interior angle

To find:

Number of sides of a polygon

Solution:

Using sum of interior angles formula:

$$S=(n-2) \times 180^{\circ}$

where "S" is the sum of interior angels and "n" is the number of sides of a polygon.

Divide by 180° on both sides.

$$\frac{S}{180^{\circ}}=\frac{(n-2) \times 180^{\circ}}{180^{\circ}}$

Cancel common factor 180°.

$$\frac{S}{180^{\circ}}=n-2$

Add 2 on both sides.

$$\frac{S}{180^{\circ}}+2=n-2+2$

$$\frac{S}{180^{\circ}}+2=n$

Switch the sides.

$$n=\frac{sum}{180^{\circ}}+2$

Therefore number of sides of a polygon is $n=\frac{sum}{180^{\circ}}+2$ .

3 0

3 years ago