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boyakko [2]
3 years ago
7

Distance and midoint

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0
What about distance and midpoint
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Find the area and the circumference of a circle with radius 3 m. Use the value 3.14 for π, and do not round your answers. Be sur
Gennadij [26K]

Circumference: 18.84 m

Area: 28.26m^{2}

Explanation

For circumference, use the formula \pi*d, where d=the diameter(the radius times 2).

For area, use the formula \pir^{2}, where r=the radius. Make sure to square the radius first before multiplying by pi!

A good way to remember these formulas is Cherry(circumference) Pi(\pi) is Delicious(diameter) and Apple(area) \pi r^{2}("are too")

8 0
3 years ago
Find z when x = 4 and y = 9 if z varies inversely with the product of x and y when x = 2, y = 4, and z = 0.5
Vera_Pavlovna [14]
8=9*87-8 9+9 765 it could be OK
8 0
3 years ago
Define mean. Then determine the mean of the following data set (22,18,38,6,24,18)
STALIN [3.7K]

Mean is the average number in the data set.

To get the average we first add all the numbers.

After we add all these numbers we then divide by the number of numbers in the data set.

So we do 22+18+38+6+24+18 which is equal to 126 there are six numbers so we divide 126 by 6. This gives us a mean of 21.

ANOTHER EXAMPLE:

Another example of this is the data set (4,65,7,34,5)

We first add all the numbers and get 115 then we divide by 5 and get 23 as the mean.



8 0
3 years ago
Does anybody know how to determine the angle again? of Q.B
Nastasia [14]

Answer:

Therefore the measur angle ACB

m\angle ACB=61.93\°

Step-by-step explanation:

Given:

ΔABC is a right Triangle at ∠A = 90°

AB = 15    ....Side Opposite to ∠ACB

AC = 8     ....Side Adjacent to ∠ACB

To Find:

m∠ACB = ?

Solution:

In Right Angle Triangle ABC, Tangent Identity we have

\tan (\angle ACB) = \dfrac{\textrm{side opposite to angle ACB}}{\textrm{side adjacent to angle ACB}}

Substituting the values we get

\tan (\angle ACB) = \dfrac{AB}{AC}=\dfrac{15}{8}=1.875\\\\\angle ACB=\tan^{-1}(1.875)\\m\angle ACB=61.93\°

Therefore the measur angle ACB

m\angle ACB=61.93\°

7 0
4 years ago
Find the slope and y-intercept of the line is parallel to y=-x-1 and passes through the point (5,-5)
Elanso [62]

Answer:

Step-by-step explanation:

y = -x - 1

the slope here is -1. A parallel line will have the same slope

y = mx + b

slope(m) = -1

(5,-5)....x = 5 and y = -5

now we sub....we are looking for b, the y int

-5 = -1(5) + b

-5 = -5 + b

-5 + 5 = b

0 = b

so ur equation is : y = -x + 0....or just y = -x

5 0
4 years ago
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