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2 years ago

Solve for x and y matrix

Mathematics

1 answer:

charle [14.2K]2 years ago

8 0

Answer:

$x=-1$

$y=5$

Step-by-step explanation:

$\begin{pmatrix}x&y\\ \:-1&4\end{pmatrix}\begin{pmatrix}2&5\\ \:4&1\end{pmatrix}=\begin{pmatrix}18&0\\ \:14&-1\end{pmatrix}$

$\begin{pmatrix}x&y\\ -1&4\end{pmatrix}\begin{pmatrix}2&5\\ 4&1\end{pmatrix}$

$=\begin{pmatrix}x\times \:2+y\times \:4&5x+y\\ 14&-1\end{pmatrix}$

$=\begin{pmatrix}18&0\\ 14&-1\end{pmatrix}$

$\begin{bmatrix}x\times \:2+y\times \:4=18\\ 5x+y=0\end{bmatrix}$

$x=-1$

$y=5$

<u>OAmalOHopeO</u>

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Problem 2

<h3>Answer: True</h3>

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Explanation:

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Step-by-step explanation:

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1) Independence between the trials (satisfied)

2) A value of n fixed , for this case is 20 (satisfied)

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So then we have all the conditions and we can assume that:

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Part b

$X \sim Bin(n =20, p=0.8)$

Part c

For this case we just need to replace into the mass function and we got:

$P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456$

Part d

For this case we want this probability: $P(X\geq 15)$

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$P(X=15)=(20C15)(0.8)^{15} (1-0.8)^{20-15}=0.17456$

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