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Jlenok [28]
3 years ago
15

A boat travels 45 miles upstream (against the current) in 5 hours. The boat travels the same distance downstream in 3 hours. Wha

t is the rate of the boat in still water? What is the rate of the current?
Mathematics
1 answer:
Leona [35]3 years ago
3 0
R=rate of boat in still water
c=rate of current
d=rt
since you're given that the time it takes to travel the same distance downstream and upstream, your equation will be d_1=d_2, or rt=rt
the rate upstream is r-c and the rate downstream is r+c (because the boat's and river's rates add up)
since you know t_1 and t_1 are 5 and 3, you can now set up 2 equations
<u>5*(r-c)=45</u> because (time upstream)*(rate upstream)=distance=45 miles
r-c=45/5=9
<u>3*(r+c)=45</u>
r+c=45/3=15
r-c=9 and r+c=15, so r=12 mi/h and c=3 mi/h
If you have any questions please ask
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Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

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By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

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1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

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