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slavikrds [6]
3 years ago
14

A set of numbers is shown below:

Mathematics
1 answer:
bonufazy [111]3 years ago
8 0
You can go through the set and test each one out:
x=0:
2(0)+3 ≥ 7?     Or 3≥7? No

x=0.6:
2(0.6)+3≥7?     4.2≥7? No.

x=2:
2(2)+3≥7?     7≥7? Yes.

x=4:
2(4)+3≥7?     11≥7? Yes.

x=6:
2(6)+3≥7?     15≥7? Yes.

The set is {2, 4, 6}.
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A boy pushes on box of mass 43 kg and it moves at an acceleration of 8.6m/s
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Answer:

Part A

W W W M W W T W W L W W

W W M M W M T W M L W M

W W T M W T T W T L W T

W W L M W L T W L L W L

W M W M M W T M W L M W

W M M M M M T M M L M M

W M T M M T T M T L M T

W M L M M L T M L L M L

W T W M T W T T W L T W

W T M M T M T T M L T M

W T T M T T T T T L T T

W T L M T L T T L L T L

W L W M L W T L W L L W

W L M M L M T L M L L M

W L T M L T T L T L L T

W L L M L L T L L L L L

Part B

There are 64 possible outcomes. The sample size is 64.

Part C

To find the probability that Erin drinks lemonade one day, tea one day, and water one day, consider all the cases in which L, T, and W occur one time. Because the order doesn't matter in this scenario, these six outcomes from the list represent the desired event: W T L, T W L, T L W, W L T, L W T, and L T W.

The size of the sample space is 64. So, the probability that Erin drinks lemonade one day, tea one day, and water one day is 3/32.

Part D

To find the probability that Erin drinks water on two days and lemonade one day, we consider all the cases in which two Ws and one L occur. Because the order doesn't matter in this scenario, these three outcomes from the list represent the event: W W L, W L W, and L W W.

The size of the sample space is 64. So, the probability that Erin drinks water two days and lemonade one day is 3/64

Step-by-step explanation:

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