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3 years ago

Find two consecutive odd integers such that 28 more than the lesser is three times the greater.

Mathematics

1 answer:

Elan Coil [88]3 years ago

8 0

Answer:

lesser odd integer =11

Greater odd integer=13

Step-by-step explanation:

let the consecutive odd integers be x,x+2

and x<x+2

3(x+2)=x+28

3x+6=x+28

3x-x=28-6

2x=22

x=11

x+2=11+3=13

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