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MakcuM [25]
3 years ago
9

Slope intercept of (2,1) and (4,0)

Mathematics
1 answer:
lutik1710 [3]3 years ago
3 0
The answer to the question

You might be interested in
Show me how to get this answer show your work
Rama09 [41]

We know that angle MKJ is comprised of angle MKL and angle LKJ. That means if we add MKL and LKJ, we should get 80 degrees, which is the measure of angle MKJ.

MKL + LKJ= MKJ \implies \\ 2x+10+3x-5=80 \implies \\ 5x+5=80 \implies\\ 5x=75 \implies \\ x=15

So, we know that our x is 15. That is not enough to tell whether KL is an angle bisector, because we have to evaluate both MKL and LKJ with x=15, so:

MKL=2(15)+10 = 40\\ LKJ=3*15-5=40

So we see that these two angles are actually bisectors, and the third question best describes this phenomenon.

6 0
3 years ago
Read 2 more answers
Place values and whole number
LenKa [72]
9. ( 1×10,000)+(5×1,000)+(4×100)+(9×1) ; fifteen thousand , four hundred - nine
7 0
4 years ago
PLZ HELP ASAP RIGHT TRIANGLES
borishaifa [10]
The correct answer is: AB = 3.11

Explanation:
Since

cos(\theta) =  \frac{base}{hypotenuse} --- (1)
\theta = 50°
base = 2

And hypotenuse = AB

Plug in the values in (1):
(1) => cos(50°) = 2/AB

=> AB = 2/0.643
=> AB = 3.11
6 0
4 years ago
A coin weighs 4/15 ounces. A different coin weighs 1/15 ounces. How much do the two coins weigh together? Write your answer as a
olchik [2.2K]

Answer:

1/3

Step-by-step explanation:

4/15 + 1/15 = 5/15

simplified its 1/3

7 0
3 years ago
Line g passes through points (5, 9) and (3, 2). Line h passes through points (9, 10) and (2, 12). Are line g and line h parallel
icang [17]

For this case we find the slopes of each of the lines:

The g line passes through the following points:

(x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)

So, the slope is:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}

Line h passes through the following points:

(x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)

So, the slope is:

m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.

It is observed that lines g and h are not parallel. We verify if they are perpendicular:

\frac {7} {2} * - \frac {2} {7} = \frac {-14} {14} = - 1

Thus, the lines are perpendicular.

Answer:

The lines are perpendicular.

8 0
3 years ago
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