All categories

3 years ago

Round 8.4102 to the nearest hundredths

Mathematics

2 answers:

Strike441 [17]3 years ago

6 0

Answer:

it's 8.41

Step-by-step explanation:

HACTEHA [7]3 years ago

4 0

Answer:

8.41

Step-by-step explanation:

You might be interested in

For a giveaway, a local radio station is putting together goodies bags. the bags will include tickets and posters. each bag will

labwork [276]

Answer:

brainly.com/question/11362948

Step-by-step explanation:

they explain nicely

7 0

3 years ago

Read 2 more answers

Please help<br><br> Solve for x and y<br> 60 points!!!!

dlinn [17]

Answer:

see explanation

Step-by-step explanation:

(1)

x + 20 and 45 are vertically opposite angles and are congruent, so

x + 20 = 45 ( subtract 20 from both sides )

x = 25

Similarly 5y and 135 are vertically opposite angles and are congruent

5y = 135 ( divide both sides by 5 )

y = 27

(2)

x + 30 and 70 are vertically opposite angles and are congruent, then

x + 30 = 70 ( subtract 30 from both sides )

x = 40

Similarly y + 50 and 110 are vertically opposite and congruent , so

x + 50 = 110 ( subtract 50 from both sides )

x = 60

6 0

2 years ago

Read 2 more answers

Determine whether a quadratic model exists for each set of values. If so, write the model.

zvonat [6]

Yes, a quadratic model does exist and its equation is f(x)=4x^2

6 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago

Help me, please<br> Which statement is true about the following pair of rectangles?

miv72 [106K]

Answer:

Step-by-step explanation:

$\frac{27}{33} = \frac{9}{11}$

5 0

3 years ago