Round 8.4102 to the nearest hundredths
2 answers:
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Answer:
So the answer for this case would be n=92 rounded up to the nearest integer
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean for the sample
population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The margin of error is given by this formula:
(a)
And on this case we have that ME =1.5 and we are interested in order to find the value of n, if we solve n from equation (b) we got:
(b)
The critical value for 92% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.04;0;1)", and we got , replacing into formula (b) we got:
So the answer for this case would be n=92 rounded up to the nearest integer
Answer:
because corresponding parts of congruent triangles ΔACD and ΔACB are Congruent
Step-by-step explanation:
Statements, Reason
bisects ∠BCD, Given
Given
∠CDA ≅ ∠CBA Right angles are ≅
Reflexive property
ΔACD ≅ ΔACB Hypotenuse Leg (HL) congrurency
CPCTC
Where:
CPCTC = Corresponding parts of Congruent Triangles are Congruent
⊥ = Perpendicular to
≅ = Congruent
∠ = Angle
Δ = Triangle.