Answer:
x=7
y=8
Step-by-step explanation:
-Given that the mean and median is the same.
-Let b=mean =median
#Given that the set is arranged in order and is even:

Hence:

-Applying the mean formula:

#Since the number are in order:

Hence, x=7 and y=8
Here we might have to find p(v intersection w) and for that we use the following formula
p(v U w) = p(v)+p(w)-p(v intersection w)
And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .
Substituting these values in the formula, we will get
0.14 = 0.13 +0.04 -p(v intersection w)
p(v intersection w) =0.13 +0.04 -0.14 = 0.03
So the required answer of the given question is 0.03 .
Answer:
Step-by-step explanation:
Multiply 100*$15 to find the loss. (1500)
Multiply 100*$21.75 to find what was made. (2175)
Subtract 2175-1500
Total=$675
Answer:
5/6
Step-by-step explanation:
- 1 has a 1/6 chance
- 2 has a 1/6 chance
- 3 has a 1/6 chance
- 5 has a 1/6 chance
- 6 has a 1/6 chance
- 1, 2, 3, 5, or 6 has a 1/6+1/6+1/6+1/6+1/6=5/6 chance
a(i). Since you are given a velocity v. time graph, the distance will be represented by:

In this case, however, we can just use simple geometry to evaluate the area under the graph v(t). I split it up into 2 trapezoids, and 1 rectangle. So, the area will be as follows:





So, the particle traveled a total of
1275m assuming it never turned back (because it says to calculate distance).
a(iii). Deceleration is a word for negative acceleration. Acceleration is the first derivative of velocity, and so deceleration is too. So, we just need to find the slope of the line that passes through t = 30 because it has a linear slope (meaning the slope doesn't change). So, we can just use simple algebra instead of calculus to figure this out. Recall from algebra that slope (m):

So, let's just pick values. I'm going to pick (25, 30) and (35, 15). Let's plug and chug:

Since it's a negative value, this means that acceleration is negative but deceleration is positive (because deceleration is negative acceleration). So, your answer is:
The deceleration of the particle at t = 30s is 3/2 or 1.5.