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lawyer [7]
3 years ago
14

Mr. Patrick wants to tile his room. When he called a contractor to measure the area of the surface that needed to be tiled, he f

ound it to be 4m². If each tile area is 500cm², how many tiles does he need?​
Mathematics
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

500÷4=125

Step-by-step explanation:

500 divided by 4 is 150 so Mr.patrick needs 150 tilws

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Vanessa uses the expressions (3x2 + 5x + 10) and (x2 – 3x – 1) to represent the length and width of her patio. Which expression
Brut [27]

The area of rectangle with length l and width w is

A=l\cdot w.

If the length of rectangle is expressed as l=3x^2 + 5x + 10 and the width of rectangle is expressed as w=x^2-3x-1, then the area of rectangle is

A=(3x^2 + 5x + 10)(x^2-3x-1)=3x^4-4x^3-8x^2-35x-10.

8 0
4 years ago
Read 2 more answers
I need help on this..... can anyone help me?
galben [10]

Answer and step-by-step explanation:

Tim Carter money made:

First 40 hours = 40 * pay per hour = 40 * 5.15 = $206 (weekly pay)

Because he works for 50 hours so next 10 hours (50-40) = 10 * (1.5*5.15)

= 10* 7.725 = $77.25

Total money he made:

= 206 + 77.25 = $283.25

Jeese Jones money amde:

First 40 hours = 40 * pay per hour = 40 * 5.15 = $206 (weekly pay)

Because he works for 47.5 hours so next 7.5 hours (47.5-40) = 7.5 * (1.5*5.15)

= 7.5 *7.725 = $57.9375

Total money Jeese Jones made:

= 206 + 57.9375 = $263.9375

Barbara Burns money made:

First 40 hours = 40 * pay per hour = 40 * 5.15 = $206 (weekly pay)

Because Barbara Burns works for 44 hours so next 4 hours (44-40) = 4 * (1.5*5.15)

= 4* 7.725 = $30.9

Total money Barbara Burns made:

= 206 + 30.9 = $236.9

Hope this help you :3

6 0
3 years ago
What are the importance of managerial accounting to the national economy pick tanazania as your case srudy
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3 years ago
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A survey organization has used the methods of our class to construct an approximate 95% confidence interval for the mean annual
lawyer [7]

Answer:

\bar X = \frac{66000+70000}{2}= 68000

We can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000

And the margin of error is given by:

ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can rewrite the margin of error like this:

ME =z_{\alpha/2}*SE

Where SE= \frac{\sigma}{\sqrt{n}}

For 95% of confidence the critical value is z_{\alpha/2}= \pm 1.96

The Standard error would be:

SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408

For 99% of confidence the critical value is z_{\alpha/2}= \pm 2.58

And the new margin of error would be:

ME = 2.58* 1020.408 = 2632.653

And then the interval would be given by:

Lower = 68000- 2632.653 = 65367.347

Upper = 68000+ 2632.653 = 70632.653

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The 95% confidence interval is given by (66000 , 70000)

We can estimate the mean with this formula:

\bar X = \frac{66000+70000}{2}= 68000

We can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000

And the margin of error is given by:

ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can rewrite the margin of error like this:

ME =z_{\alpha/2}*SE

Where SE= \frac{\sigma}{\sqrt{n}}

For 95% of confidence the critical value is z_{\alpha/2}= \pm 1.96

The Standard error would be:

SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408

For 99% of confidence the critical value is z_{\alpha/2}= \pm 2.58

And the new margin of error would be:

ME = 2.58* 1020.408 = 2632.653

And then the interval would be given by:

Lower = 68000- 2632.653 = 65367.347

Upper = 68000+ 2632.653 = 70632.653

7 0
4 years ago
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