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FinnZ [79.3K]
3 years ago
11

How to simplify, assuming all variables are nonnegative? Please help!

Mathematics
1 answer:
FromTheMoon [43]3 years ago
8 0

Step-by-step explanation:

please mark me as brainlest

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The product of victors saving and 9 is 435
denpristay [2]
=3,915

product is use for multiplying
5 0
3 years ago
Whats the extreme value?y=3(x+5)^(2)-4
natta225 [31]

Answer:

-4

Step-by-step explanation:

  • y = 3(x+5)²-4
  • y= 3(x²+10x+25)-4
  • y= 3x²+30x+75-4
  • y= 3x²+30x+71

Derivate the function

  • y' = 6x+30

solve the equation y'= 0

  • y'= 6x+30
  • 6x+30= 0
  • 6x= -30
  • x = -5

The extrme value of y is reached in -5

y = 3(-5+5)²-4= -4

6 0
3 years ago
Divide each of the following numbers by 10. a. 9.48 b. .6 c. 84.5 d. .0024 e. .3678 f. 25
DedPeter [7]

Answer:

1.) 0.948

2.)0.06

3.)8.45

4.).00024

5.)0.03678

6.)2.5

Hope this helps you some!!

6 0
4 years ago
Read 2 more answers
The ages of the winners of a cycling tournament are approximately bell-shaped. The mean age is 27.2 years, with a standard devia
elena-14-01-66 [18.8K]

Answer:

a. z-score = -1.2

b. The age 23 years old is -1.2 standard deviations below the mean

c. The age is not unusual

Step-by-step explanation:

a. Transformation to z-score

Mathematically;

z-score = (x - μ)/σ

where σ and μ are the standard deviation and the mean respectively.

From the question, x = 23, μ = 27.2 and σ = 3.5

Let’s put these into the equation;

z-score = (23-27.2)/3.5 = -1.2

b. Interpretation of result

The interpretation is that 23 years old is -1.2 standard deviations below the mean

c. Determination

The age is not unusual. This is because any z-value below -2 or above 2 is considered unusual

-1.2 is above -2 and thus it is not unusual

7 0
3 years ago
State the domain of the numbers displayed in column x and column y. x y
ella [17]

We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:

The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.

The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.


5 0
3 years ago
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